Q1) \(x + 5\over 2\) - \(x + 9\over 7\) = [ \(5 x + 17\over 14\) ]
Q1) \(3\over x+ 2\) + \(9\over x +2\) = [ \(12 x + 24\over x^{2}+ 4 x +4 \)]
Q1) \(6\over x+ 4\) + \(8\over x +7\) = [ \(14 x + 74\over x^{2}+11x +28 \)]
Q2) \(x + 3\over 2\) + \(x + 5\over 4\) = [ \(3 x + 11\over 4\) ]
Q2) \(9\over x+ 6\) + \(3\over x +2\) = [ \(12 x + 36\over x^{2}+ 8 x +12 \)]
Q2) \(5\over x+ 4\) + \(3\over x +2\) = [ \(8 x + 22\over x^{2}+6x +8 \)]
Q3) \(x + 10\over 2\) - \(x + 10\over 8\) = [ \(3 x + 30\over 8\) ]
Q3) \(7\over x+ 6\) + \(9\over x +7\) = [ \(16 x + 103\over x^{2}+ 13 x +42 \)]
Q3) \(3\over x+ 2\) + \(8\over x -2\) = [ \(11x + 10\over x^{2} -4 \)]
Q4) \(x + 9\over 5\) - \(x + 10\over 8\) = [ \(3 x + 22\over 40\) ]
Q4) \(7\over x+ 2\) - \(5\over x +4\) = [ \(2 x + 18\over x^{2}+ 6 x +8 \)]
Q4) \(8\over x+ 4\) + \(9\over x +6\) = [ \(17 x + 84\over x^{2}+10x +24 \)]
Q5) \(x + 7\over 4\) - \(x + 9\over 7\) = [ \(3 x + 13\over 28\) ]
Q5) \(10\over x+ 8\) - \(8\over x +2\) = [ \(2 x -44\over x^{2}+ 10 x +16 \)]
Q5) \(7\over x+ 6\) + \(9\over x +3\) = [ \(16 x + 75\over x^{2}+9x +18 \)]
Q6) \(x + 9\over 3\) - \(x + 10\over 8\) = [ \(5 x + 42\over 24\) ]
Q6) \(9\over x+ 4\) - \(7\over x +3\) = [ \(2 x -1\over x^{2}+ 7 x +12 \)]
Q6) \(6\over x+ 5\) + \(8\over x -2\) = [ \(14 x + 28\over x^{2}+3x -10 \)]
Q7) \(x + 8\over 4\) + \(x + 10\over 7\) = [ \(11x + 96\over 28\) ]
Q7) \(10\over x+ 6\) - \(6\over x +2\) = [ \(4 x -16\over x^{2}+ 8 x +12 \)]
Q7) \(9\over x+ 8\) + \(5\over x -6\) = [ \(14 x -14\over x^{2}+2x -48 \)]
Q8) \(x + 6\over 3\) + \(x + 6\over 3\) = [ \(2 x + 12\over 3\) ]
Q8) \(10\over x+ 8\) - \(5\over x +4\) = [ \(5 x\over x^{2}+ 12 x +32 \)]
Q8) \(9\over x+ 8\) - \(5\over x -9\) = [ \(4 x -121\over x^{2}-x -72 \)]
Q9) \(x + 7\over 2\) - \(x + 7\over 5\) = [ \(3 x + 21\over 10\) ]
Q9) \(8\over x+ 6\) - \(6\over x +5\) = [ \(2 x + 4\over x^{2}+ 11x +30 \)]
Q9) \(10\over x+ 5\) - \(5\over x -6\) = [ \(5 x -85\over x^{2}-x -30 \)]
Q10) \(x + 7\over 2\) + \(x + 8\over 7\) = [ \(9 x + 65\over 14\) ]
Q10) \(8\over x+ 7\) + \(5\over x +4\) = [ \(13 x + 67\over x^{2}+ 11x +28 \)]
Q10) \(4\over x+ 2\) + \(5\over x -3\) = [ \(9 x -2\over x^{2}-x -6 \)]