Q1) There are 7 blue beads ,and 4 red beads in a bag.
a) What is the probability of picking a blue bead?
b) What is the probability of picking a red bead?
[ a) P(blue)=\(\frac{7}{11}\).
b) P(red)=\(\frac{4}{11}\).
]

Q1) There were 9 green pencils ,and 3 purple pencils in a box . Two pencils were picked and not replaced. What was the probability they were both green ?
[ \(\frac{6}{11}\) ]

Q1) There are 10 green beads ,and some yellow beads in a bag . 3 extra yellow beads were added. Two beads were picked at random and not replaced. The probability they were both green was \(\frac{45}{136}\). How many yellow beads were there to begin with ?
[ 4 ]

Q2) There are 9 red beads ,and 4 purple beads in a bag.
a) What is the probability of picking a red bead?
b) What is the probability of picking a purple bead?
[ a) P(red)=\(\frac{9}{13}\).
b) P(purple)=\(\frac{4}{13}\).
]

Q2) There were 4 yellow apples ,and 10 blue apples in a packet . Two apples were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{6}{91}\) ]

Q2) There are 7 red sweets ,and some green sweets in a tin . 9 extra green sweets were added. Two sweets were picked at random and not replaced. The probability they were both red was \(\frac{21}{325}\). How many green sweets were there to begin with ?
[ 10 ]

Q3) There are 2 purple beads ,and 4 blue beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a blue bead?
[ a) P(purple)=\(\frac{1}{3}\).
b) P(blue)=\(\frac{2}{3}\).
]

Q3) There were 10 yellow pencils ,and 2 blue pencils in a draw . Two pencils were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{15}{22}\) ]

Q3) There were 10 purple beads ,and some blue beads in a bag . Two beads were picked at random and not replaced. The probability they were both purple was \(\frac{3}{7}\). How many blue beads were there ?
[ 5 ]

Q4) There are 4 red beads ,and 2 green beads in a bag.
a) What is the probability of picking a red bead?
b) What is the probability of picking a green bead?
[ a) P(red)=\(\frac{2}{3}\).
b) P(green)=\(\frac{1}{3}\).
]

Q4) There were 8 green apples ,and 2 red apples in a tray . Two apples were picked and not replaced. What was the probability they were both green ?
[ \(\frac{28}{45}\) ]

Q4) There are 10 purple pencils ,and some blue pencils in a box . 8 extra blue pencils were added. Two pencils were picked at random and not replaced. The probability they were both purple was \(\frac{5}{42}\). How many blue pencils were there to begin with ?
[ 10 ]

Q5) There are 3 green beads ,and 7 yellow beads in a bag.
a) What is the probability of picking a green bead?
b) What is the probability of picking a yellow bead?
[ a) P(green)=\(\frac{3}{10}\).
b) P(yellow)=\(\frac{7}{10}\).
]

Q5) There were 6 blue sweets ,and 7 green sweets in a box . Two sweets were picked and not replaced. What was the probability they were both blue ?
[ \(\frac{5}{26}\) ]

Q5) There are 5 red sweets ,and some purple sweets in a draw . 8 extra purple sweets were added. Two sweets were picked at random and not replaced. The probability they were both red was \(\frac{2}{21}\). How many purple sweets were there to begin with ?
[ 2 ]