Q1) \(x + 7\over 3\) ÷ \(4 \over {x + 7}\) = [ \(x^2 + 14 x + 49\over 12\) ]

Q1) \(x + 2\over 7\) x \(6 \over{ x + 7}\) = [ \(6( x + 2) \over 7 ( x + 7)\) ]

Q1) \(x + 5\over 9\) x \(x + 1\over x + 5\) = [ \(x + 1\over 9\) ]

Q2) \(x + 4\over 2\) x \(x + 4\over 4\) = [ \(x^2 + 8 x + 16\over 8\) ]

Q2) \(x + 5\over 7\) ÷ \({ x + 8} \over 3 \) = [ \(3( x + 5) \over 7 ( x + 8)\) ]

Q2) \(x + 7\over 8\) ÷ \( x + 7\over x + 7\) = [ \(x + 7\over 8\) ]

Q3) \(x + 7\over 3\) ÷ \(7 \over {x + 6}\) = [ \(x^2 + 13 x + 42\over 21\) ]

Q3) \(x + 4\over 7\) x \(8 \over{ x + 7}\) = [ \(8( x + 4) \over 7 ( x + 7)\) ]

Q3) \(x + 1\over 4\) x \(x + 8\over x + 1\) = [ \(x + 8\over 4\) ]

Q4) \(x + 7\over 4\) ÷ \(7 \over {x + 3}\) = [ \(x^2 + 10 x + 21\over 28\) ]

Q4) \(x + 6\over 1\) x \(3 \over{ x + 5}\) = [ \(3( x + 6) \over( x + 5)\) ]

Q4) \(x + 7\over 5\) ÷ \( x + 7\over x + 8\) = [ \(x + 8\over 5\) ]

Q5) \(x + 10\over 4\) x \(x + 4\over 5\) = [ \(x^2 + 14 x + 40\over 20\) ]

Q5) \(x + 8\over 1\) x \(1 \over{ x + 6}\) = [ \(1( x + 8) \over( x + 6)\) ]

Q5) \(x + 1\over 8\) x \(x + 3\over x + 1\) = [ \(x + 3\over 8\) ]

Q6) \(x + 8\over 4\) x \(x + 1\over 2\) = [ \(x^2 + 9 x + 8\over 8\) ]

Q6) \(x + 1\over 3\) ÷ \({ x + 8} \over 5 \) = [ \(5( x + 1) \over 3 ( x + 8)\) ]

Q6) \(x + 6\over 9\) x \(x + 3\over x + 6\) = [ \(x + 3\over 9\) ]

Q7) \(x + 1\over 5\) ÷ \(3 \over {x + 6}\) = [ \(x^2 + 7 x + 6\over 15\) ]

Q7) \(x + 2\over 1\) x \(1 \over{ x + 8}\) = [ \(1( x + 2) \over( x + 8)\) ]

Q7) \(x + 3\over 2\) ÷ \( x + 3\over x + 7\) = [ \(x + 7\over 2\) ]

Q8) \(x + 9\over 6\) x \(x + 5\over 7\) = [ \(x^2 + 14 x + 45\over 42\) ]

Q8) \(x + 9\over 10\) x \(7 \over{ x + 7}\) = [ \(7( x + 9) \over 10 ( x + 7)\) ]

Q8) \(x + 10\over 10\) x \(x + 10\over x + 10\) = [ \(x + 10\over 10\) ]

Q9) \(x + 1\over 10\) x \(x + 1\over 8\) = [ \(x^2 + 2 x + 1\over 80\) ]

Q9) \(x + 1\over 3\) x \(1 \over{ x + 4}\) = [ \(1( x + 1) \over 3 ( x + 4)\) ]

Q9) \(x + 6\over 8\) x \(x + 10\over x + 6\) = [ \(x + 10\over 8\) ]

Q10) \(x + 7\over 9\) x \(x + 10\over 5\) = [ \(x^2 + 17 x + 70\over 45\) ]

Q10) \(x + 7\over 5\) ÷ \({ x + 9} \over 3 \) = [ \(3( x + 7) \over 5 ( x + 9)\) ]

Q10) \(x + 4\over 5\) x \(x + 3\over x + 4\) = [ \(x + 3\over 5\) ]