Q1) \(x + 2\over 9\) ÷ \(7 \over {x + 7}\) = [ \(x^2 + 9 x + 14\over 63\) ]

Q1) \(x + 4\over 2\) x \(3 \over{ x + 7}\) = [ \(3( x + 4) \over 2 ( x + 7)\) ]

Q1) \(x + 10\over 5\) x \(x + 4\over x + 10\) = [ \(x + 4\over 5\) ]

Q2) \(x + 5\over 2\) x \(x + 5\over 6\) = [ \(x^2 + 10 x + 25\over 12\) ]

Q2) \(x + 2\over 9\) ÷ \({ x + 1} \over 5 \) = [ \(5( x + 2) \over 9 ( x + 1)\) ]

Q2) \(x + 7\over 2\) ÷ \( x + 7\over x + 4\) = [ \(x + 4\over 2\) ]

Q3) \(x + 2\over 8\) ÷ \(10 \over {x + 2}\) = [ \(x^2 + 4 x + 4\over 80\) ]

Q3) \(x + 8\over 3\) ÷ \({ x + 5} \over 2 \) = [ \(2( x + 8) \over 3 ( x + 5)\) ]

Q3) \(x + 4\over 3\) ÷ \( x + 4\over x + 4\) = [ \(x + 4\over 3\) ]

Q4) \(x + 7\over 4\) ÷ \(7 \over {x + 10}\) = [ \(x^2 + 17 x + 70\over 28\) ]

Q4) \(x + 6\over 2\) ÷ \({ x + 1} \over 5 \) = [ \(5( x + 6) \over 2 ( x + 1)\) ]

Q4) \(x + 10\over 2\) x \(x + 3\over x + 10\) = [ \(x + 3\over 2\) ]

Q5) \(x + 3\over 3\) x \(x + 5\over 8\) = [ \(x^2 + 8 x + 15\over 24\) ]

Q5) \(x + 3\over 1\) ÷ \({ x + 5} \over 1 \) = [ \(1( x + 3) \over( x + 5)\) ]

Q5) \(x + 8\over 3\) ÷ \( x + 8\over x + 5\) = [ \(x + 5\over 3\) ]

Q6) \(x + 2\over 10\) x \(x + 6\over 8\) = [ \(x^2 + 8 x + 12\over 80\) ]

Q6) \(x + 5\over 3\) ÷ \({ x + 1} \over 7 \) = [ \(7( x + 5) \over 3 ( x + 1)\) ]

Q6) \(x + 7\over 6\) ÷ \( x + 7\over x + 8\) = [ \(x + 8\over 6\) ]

Q7) \(x + 10\over 4\) ÷ \(5 \over {x + 4}\) = [ \(x^2 + 14 x + 40\over 20\) ]

Q7) \(x + 4\over 10\) ÷ \({ x + 6} \over 3 \) = [ \(3( x + 4) \over 10 ( x + 6)\) ]

Q7) \(x + 7\over 6\) x \(x + 10\over x + 7\) = [ \(x + 10\over 6\) ]

Q8) \(x + 1\over 8\) x \(x + 6\over 9\) = [ \(x^2 + 7 x + 6\over 72\) ]

Q8) \(x + 6\over 7\) ÷ \({ x + 1} \over 5 \) = [ \(5( x + 6) \over 7 ( x + 1)\) ]

Q8) \(x + 3\over 4\) ÷ \( x + 3\over x + 4\) = [ \(x + 4\over 4\) ]

Q9) \(x + 5\over 2\) ÷ \(4 \over {x + 1}\) = [ \(x^2 + 6 x + 5\over 8\) ]

Q9) \(x + 2\over 1\) ÷ \({ x + 3} \over 2 \) = [ \(2( x + 2) \over( x + 3)\) ]

Q9) \(x + 2\over 3\) ÷ \( x + 2\over x + 3\) = [ \(x + 3\over 3\) ]

Q10) \(x + 4\over 3\) ÷ \(8 \over {x + 1}\) = [ \(x^2 + 5 x + 4\over 24\) ]

Q10) \(x + 5\over 5\) x \(8 \over{ x + 1}\) = [ \(8( x + 5) \over 5 ( x + 1)\) ]

Q10) \(x + 8\over 3\) ÷ \( x + 8\over x + 10\) = [ \(x + 10\over 3\) ]