Q1) \(x + 8\over 6\) x \(x + 10\over 3\) = [ \(x^2 + 18 x + 80\over 18\) ]

Q1) \(x + 8\over 9\) ÷ \({ x + 6} \over 8 \) = [ \(8( x + 8) \over 9 ( x + 6)\) ]

Q1) \(x + 1\over 10\) x \(x + 9\over x + 1\) = [ \(x + 9\over 10\) ]

Q2) \(x + 6\over 10\) x \(x + 8\over 5\) = [ \(x^2 + 14 x + 48\over 50\) ]

Q2) \(x + 1\over 2\) ÷ \({ x + 7} \over 7 \) = [ \(7( x + 1) \over 2 ( x + 7)\) ]

Q2) \(x + 10\over 8\) x \(x + 2\over x + 10\) = [ \(x + 2\over 8\) ]

Q3) \(x + 8\over 3\) ÷ \(10 \over {x + 5}\) = [ \(x^2 + 13 x + 40\over 30\) ]

Q3) \(x + 10\over 7\) x \(10 \over{ x + 1}\) = [ \(10( x + 10) \over 7 ( x + 1)\) ]

Q3) \(x + 8\over 10\) x \(x + 4\over x + 8\) = [ \(x + 4\over 10\) ]

Q4) \(x + 3\over 4\) ÷ \(6 \over {x + 9}\) = [ \(x^2 + 12 x + 27\over 24\) ]

Q4) \(x + 6\over 1\) ÷ \({ x + 7} \over 1 \) = [ \(1( x + 6) \over( x + 7)\) ]

Q4) \(x + 6\over 10\) x \(x + 2\over x + 6\) = [ \(x + 2\over 10\) ]

Q5) \(x + 8\over 8\) x \(x + 9\over 3\) = [ \(x^2 + 17 x + 72\over 24\) ]

Q5) \(x + 10\over 5\) x \(3 \over{ x + 2}\) = [ \(3( x + 10) \over 5 ( x + 2)\) ]

Q5) \(x + 7\over 2\) x \(x + 8\over x + 7\) = [ \(x + 8\over 2\) ]

Q6) \(x + 9\over 10\) ÷ \(4 \over {x + 9}\) = [ \(x^2 + 18 x + 81\over 40\) ]

Q6) \(x + 6\over 8\) x \(5 \over{ x + 1}\) = [ \(5( x + 6) \over 8 ( x + 1)\) ]

Q6) \(x + 1\over 10\) ÷ \( x + 1\over x + 3\) = [ \(x + 3\over 10\) ]

Q7) \(x + 3\over 3\) ÷ \(5 \over {x + 5}\) = [ \(x^2 + 8 x + 15\over 15\) ]

Q7) \(x + 6\over 1\) ÷ \({ x + 8} \over 5 \) = [ \(5( x + 6) \over( x + 8)\) ]

Q7) \(x + 5\over 3\) x \(x + 2\over x + 5\) = [ \(x + 2\over 3\) ]

Q8) \(x + 9\over 7\) x \(x + 3\over 3\) = [ \(x^2 + 12 x + 27\over 21\) ]

Q8) \(x + 10\over 3\) x \(1 \over{ x + 2}\) = [ \(1( x + 10) \over 3 ( x + 2)\) ]

Q8) \(x + 7\over 6\) x \(x + 3\over x + 7\) = [ \(x + 3\over 6\) ]

Q9) \(x + 9\over 10\) ÷ \(8 \over {x + 10}\) = [ \(x^2 + 19 x + 90\over 80\) ]

Q9) \(x + 4\over 2\) ÷ \({ x + 5} \over 3 \) = [ \(3( x + 4) \over 2 ( x + 5)\) ]

Q9) \(x + 7\over 5\) ÷ \( x + 7\over x + 10\) = [ \(x + 10\over 5\) ]

Q10) \(x + 7\over 8\) ÷ \(8 \over {x + 6}\) = [ \(x^2 + 13 x + 42\over 64\) ]

Q10) \(x + 5\over 10\) x \(9 \over{ x + 9}\) = [ \(9( x + 5) \over 10 ( x + 9)\) ]

Q10) \(x + 9\over 7\) ÷ \( x + 9\over x + 8\) = [ \(x + 8\over 7\) ]