Mr Daniels Maths
Algebraic Fractions Simplification

Set 1

Set 2

Set 3

Q1) \({x^2 -x-6}\over{x+2}\) = [ \(x-3\) ]

Q1) \({x-2}\over{x^2 -4}\) = [ \(1\over{x+2}\) ]

Q1) \({2x^2 +15x+18}\over{x+6}\) = [ \(2x+3\) ]

Q2) \({x+2\over{x^2 -x-6}}\) = [ \(1\over{x-3}\) ]

Q2) \({x^2 -49}\over{x+7}\) = [ \(x-7\) ]

Q2) \({2x^2 -10x+8}\over{x-4}\) = [ \(2x-2\) ]

Q3) \({x-7\over{x^2 -5x-14}}\) = [ \(1\over{x+2}\) ]

Q3) \({x+4}\over{x^2 -16}\) = [ \(1\over{x-4}\) ]

Q3) \({5x^2 +33x+18}\over{x+6}\) = [ \(5x+3\) ]

Q4) \({x-2\over{x^2 -5x+6}}\) = [ \(1\over{x-3}\) ]

Q4) \({x^2 -36}\over{x+6}\) = [ \(x-6\) ]

Q4) \({5x^2 +4x-12}\over{x+2}\) = [ \(5x-6\) ]

Q5) \({x^2 +5x-14}\over{x+7}\) = [ \(x-2\) ]

Q5) \({x^2 -16}\over{x-4}\) = [ \(x+4\) ]

Q5) \({2x^2 -16x+30}\over{x-5}\) = [ \(2x-6\) ]

Q6) \({x-4\over{x^2 +x-20}}\) = [ \(1\over{x+5}\) ]

Q6) \({x^2 -25}\over{x+5}\) = [ \(x-5\) ]

Q6) \({4x^2 +23x+15}\over{x+5}\) = [ \(4x+3\) ]

Q7) \({x-2\over{x^2 +4x-12}}\) = [ \(1\over{x+6}\) ]

Q7) \({x-3}\over{x^2 -9}\) = [ \(1\over{x+3}\) ]

Q7) \({5x^2 -6x-8}\over{x-2}\) = [ \(5x+4\) ]

Q8) \({x^2 +6x+8}\over{x+2}\) = [ \(x+4\) ]

Q8) \({x-7}\over{x^2 -49}\) = [ \(1\over{x+7}\) ]

Q8) \({2x^2 +12x+18}\over{x+3}\) = [ \(2x+6\) ]

Q9) \({x^2 +7x+10}\over{x+5}\) = [ \(x+2\) ]

Q9) \({x+3}\over{x^2 -9}\) = [ \(1\over{x-3}\) ]

Q9) \({2x^2 -9x+10}\over{x-2}\) = [ \(2x-5\) ]

Q10) \({x^2 +7x+10}\over{x+2}\) = [ \(x+5\) ]

Q10) \({x-8}\over{x^2 -64}\) = [ \(1\over{x+8}\) ]

Q10) \({5x^2 -15x-20}\over{x-4}\) = [ \(5x+5\) ]