Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{5}{6}\) - \(\frac{1}{2}\) = [ \(\frac{1}{3}\)]

Q1) 1\(\frac{1}{3}\) - \(\frac{4}{7}\) = [ \(\frac{16}{21}\)]

Q1) 5\(\frac{1}{2}\) - 1\(\frac{4}{19}\) = [ 4\(\frac{11}{38}\)]

Q2) \(\frac{5}{6}\) - \(\frac{5}{8}\) = [ \(\frac{5}{24}\)]

Q2) 1\(\frac{1}{8}\) - \(\frac{3}{4}\) = [ \(\frac{3}{8}\)]

Q2) 2\(\frac{1}{2}\) - 1\(\frac{7}{20}\) = [ 1\(\frac{3}{20}\)]

Q3) \(\frac{1}{2}\) - \(\frac{4}{9}\) = [ \(\frac{1}{18}\)]

Q3) 1\(\frac{1}{5}\) - \(\frac{4}{7}\) = [ \(\frac{22}{35}\)]

Q3) 5\(\frac{1}{2}\) - 2\(\frac{1}{2}\) = [ 3]

Q4) \(\frac{3}{7}\) - \(\frac{1}{3}\) = [ \(\frac{2}{21}\)]

Q4) 1\(\frac{1}{3}\) - \(\frac{4}{5}\) = [ \(\frac{8}{15}\)]

Q4) 2\(\frac{2}{3}\) - 1\(\frac{1}{3}\) = [ 1\(\frac{1}{3}\)]

Q5) \(\frac{2}{3}\) - \(\frac{1}{4}\) = [ \(\frac{5}{12}\)]

Q5) 1\(\frac{2}{3}\) - \(\frac{4}{5}\) = [ \(\frac{13}{15}\)]

Q5) 2\(\frac{2}{3}\) - 1\(\frac{8}{9}\) = [ \(\frac{7}{9}\)]

Q6) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q6) 1\(\frac{1}{3}\) - \(\frac{5}{6}\) = [ \(\frac{1}{2}\)]

Q6) 2\(\frac{1}{4}\) - 1\(\frac{9}{14}\) = [ \(\frac{17}{28}\)]

Q7) \(\frac{2}{3}\) - \(\frac{3}{5}\) = [ \(\frac{1}{15}\)]

Q7) 1\(\frac{2}{5}\) - \(\frac{2}{3}\) = [ \(\frac{11}{15}\)]

Q7) 1\(\frac{9}{13}\) - 1\(\frac{2}{3}\) = [ \(\frac{1}{39}\)]

Q8) \(\frac{3}{4}\) - \(\frac{3}{5}\) = [ \(\frac{3}{20}\)]

Q8) 1\(\frac{1}{4}\) - \(\frac{1}{2}\) = [ \(\frac{3}{4}\)]

Q8) 2\(\frac{1}{3}\) - 1\(\frac{7}{15}\) = [ \(\frac{13}{15}\)]

Q9) \(\frac{3}{4}\) - \(\frac{2}{3}\) = [ \(\frac{1}{12}\)]

Q9) 1\(\frac{3}{4}\) - \(\frac{4}{5}\) = [ \(\frac{19}{20}\)]

Q9) 3\(\frac{1}{4}\) - 1\(\frac{4}{9}\) = [ 1\(\frac{29}{36}\)]

Q10) \(\frac{6}{7}\) - \(\frac{1}{2}\) = [ \(\frac{5}{14}\)]

Q10) 1\(\frac{1}{5}\) - \(\frac{7}{8}\) = [ \(\frac{13}{40}\)]

Q10) 1\(\frac{3}{4}\) - 1\(\frac{4}{7}\) = [ \(\frac{5}{28}\)]