Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{5}{8}\) - \(\frac{3}{5}\) = [ \(\frac{1}{40}\)]

Q1) 1\(\frac{1}{4}\) - \(\frac{3}{7}\) = [ \(\frac{23}{28}\)]

Q1) 1\(\frac{5}{6}\) - 1\(\frac{5}{9}\) = [ \(\frac{5}{18}\)]

Q2) \(\frac{1}{2}\) - \(\frac{2}{5}\) = [ \(\frac{1}{10}\)]

Q2) 1\(\frac{2}{7}\) - \(\frac{2}{3}\) = [ \(\frac{13}{21}\)]

Q2) 2\(\frac{1}{3}\) - 1\(\frac{6}{7}\) = [ \(\frac{10}{21}\)]

Q3) \(\frac{3}{4}\) - \(\frac{1}{2}\) = [ \(\frac{1}{4}\)]

Q3) 1\(\frac{1}{4}\) - \(\frac{2}{3}\) = [ \(\frac{7}{12}\)]

Q3) 3\(\frac{2}{3}\) - 2\(\frac{1}{3}\) = [ 1\(\frac{1}{3}\)]

Q4) \(\frac{6}{7}\) - \(\frac{3}{5}\) = [ \(\frac{9}{35}\)]

Q4) 1\(\frac{1}{2}\) - \(\frac{6}{7}\) = [ \(\frac{9}{14}\)]

Q4) 1\(\frac{4}{7}\) - 1\(\frac{1}{4}\) = [ \(\frac{9}{28}\)]

Q5) \(\frac{5}{6}\) - \(\frac{2}{5}\) = [ \(\frac{13}{30}\)]

Q5) 1\(\frac{1}{7}\) - \(\frac{3}{4}\) = [ \(\frac{11}{28}\)]

Q5) 5\(\frac{1}{2}\) - 1\(\frac{9}{19}\) = [ 4\(\frac{1}{38}\)]

Q6) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q6) 1\(\frac{1}{5}\) - \(\frac{3}{7}\) = [ \(\frac{27}{35}\)]

Q6) 5\(\frac{1}{2}\) - 1\(\frac{1}{2}\) = [ 4]

Q7) \(\frac{2}{3}\) - \(\frac{2}{9}\) = [ \(\frac{4}{9}\)]

Q7) 1\(\frac{1}{2}\) - \(\frac{3}{5}\) = [ \(\frac{9}{10}\)]

Q7) 2\(\frac{1}{3}\) - 1\(\frac{7}{9}\) = [ \(\frac{5}{9}\)]

Q8) \(\frac{3}{4}\) - \(\frac{4}{7}\) = [ \(\frac{5}{28}\)]

Q8) 1\(\frac{1}{8}\) - \(\frac{1}{2}\) = [ \(\frac{5}{8}\)]

Q8) 3\(\frac{1}{2}\) - 1\(\frac{5}{11}\) = [ 2\(\frac{1}{22}\)]

Q9) \(\frac{2}{3}\) - \(\frac{2}{5}\) = [ \(\frac{4}{15}\)]

Q9) 1\(\frac{1}{3}\) - \(\frac{2}{3}\) = [ \(\frac{2}{3}\)]

Q9) 5\(\frac{1}{2}\) - 1\(\frac{1}{10}\) = [ 4\(\frac{2}{5}\)]

Q10) \(\frac{7}{8}\) - \(\frac{5}{6}\) = [ \(\frac{1}{24}\)]

Q10) 1\(\frac{1}{7}\) - \(\frac{4}{7}\) = [ \(\frac{4}{7}\)]

Q10) 2\(\frac{1}{5}\) - 1\(\frac{7}{9}\) = [ \(\frac{19}{45}\)]