Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{3}{4}\) - \(\frac{3}{5}\) = [ \(\frac{3}{20}\)]

Q1) 1\(\frac{2}{5}\) - \(\frac{5}{9}\) = [ \(\frac{38}{45}\)]

Q1) 4\(\frac{1}{3}\) - 1\(\frac{10}{17}\) = [ 2\(\frac{38}{51}\)]

Q2) \(\frac{3}{5}\) - \(\frac{4}{9}\) = [ \(\frac{7}{45}\)]

Q2) 1\(\frac{1}{3}\) - \(\frac{2}{5}\) = [ \(\frac{14}{15}\)]

Q2) 1\(\frac{5}{6}\) - 1\(\frac{4}{9}\) = [ \(\frac{7}{18}\)]

Q3) \(\frac{3}{5}\) - \(\frac{1}{2}\) = [ \(\frac{1}{10}\)]

Q3) 1\(\frac{1}{5}\) - \(\frac{2}{3}\) = [ \(\frac{8}{15}\)]

Q3) 3\(\frac{1}{4}\) - 1\(\frac{9}{13}\) = [ 1\(\frac{29}{52}\)]

Q4) \(\frac{3}{4}\) - \(\frac{1}{2}\) = [ \(\frac{1}{4}\)]

Q4) 1\(\frac{1}{2}\) - \(\frac{3}{4}\) = [ \(\frac{3}{4}\)]

Q4) 1\(\frac{2}{3}\) - 1\(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q5) \(\frac{1}{2}\) - \(\frac{3}{8}\) = [ \(\frac{1}{8}\)]

Q5) 1\(\frac{1}{3}\) - \(\frac{3}{4}\) = [ \(\frac{7}{12}\)]

Q5) 2\(\frac{2}{3}\) - 1\(\frac{1}{3}\) = [ 1\(\frac{1}{3}\)]

Q6) \(\frac{4}{5}\) - \(\frac{1}{2}\) = [ \(\frac{3}{10}\)]

Q6) 1\(\frac{3}{7}\) - \(\frac{6}{7}\) = [ \(\frac{4}{7}\)]

Q6) 4\(\frac{1}{2}\) - 1\(\frac{1}{6}\) = [ 3\(\frac{1}{3}\)]

Q7) \(\frac{2}{3}\) - \(\frac{3}{7}\) = [ \(\frac{5}{21}\)]

Q7) 1\(\frac{3}{4}\) - \(\frac{6}{7}\) = [ \(\frac{25}{28}\)]

Q7) 2\(\frac{1}{2}\) - 1\(\frac{8}{9}\) = [ \(\frac{11}{18}\)]

Q8) \(\frac{2}{3}\) - \(\frac{1}{2}\) = [ \(\frac{1}{6}\)]

Q8) 1\(\frac{2}{5}\) - \(\frac{3}{7}\) = [ \(\frac{34}{35}\)]

Q8) 3\(\frac{1}{2}\) - 3\(\frac{1}{4}\) = [ \(\frac{1}{4}\)]

Q9) \(\frac{3}{4}\) - \(\frac{5}{8}\) = [ \(\frac{1}{8}\)]

Q9) 1\(\frac{3}{4}\) - \(\frac{7}{9}\) = [ \(\frac{35}{36}\)]

Q9) 1\(\frac{2}{5}\) - 1\(\frac{1}{4}\) = [ \(\frac{3}{20}\)]

Q10) \(\frac{3}{4}\) - \(\frac{2}{9}\) = [ \(\frac{19}{36}\)]

Q10) 1\(\frac{1}{2}\) - \(\frac{7}{8}\) = [ \(\frac{5}{8}\)]

Q10) 2\(\frac{1}{2}\) - 1\(\frac{2}{17}\) = [ 1\(\frac{13}{34}\)]