Mr Daniels Maths
Functions Inverse

Set 1

Set 2

Set 3

Q1) \(h(x) =9{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over9\)]

Q1) h(x) = 7 x -7. Find h'(x). [ \(h'(x) \)= \({x +7}\over7\)]

Q1) h(x) =\( 9 x^ 3 -4\). Find h'(x). [ h'(x)= \( \sqrt[3]{{x +4}\over 9} \)]

Q2) g(x) =x + 3. Find g'(x). [ g'(x) = x -3]

Q2) f(x) = 2 x + 5. Find f'(x). [ \(f'(x) \)= \({x -5}\over2\)]

Q2) g(x) =\( 10 x^ 3 -2\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x +2}\over 10} \)]

Q3) h(x) =x -7. Find h'(x). [ h'(x) = x +7]

Q3) h(x) = 4 x -10. Find h'(x). [ \(h'(x) \)= \({x +10}\over4\)]

Q3) g(x) =\( 5 x^ 2 + 7\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x -7}\over 5} \)]

Q4) \(f(x) =4{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over4\)]

Q4) g(x) = \(x\over 2\) -2. Find g'(x). [ \(g'(x) \)= \(2(x +2)\)]

Q4) g(x) =\(x^ 2 -5\). Find g'(x). [ g'(x)= \( \sqrt[2]{x +5} \)]

Q5) \(f(x) =8{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over8\)]

Q5) h(x) = 5 x + 8. Find h'(x). [ \(h'(x) \)= \({x -8}\over5\)]

Q5) g(x) =\( 10 x^ 2 -5\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x +5}\over 10} \)]

Q6) \(h(x) =3{x}. \) Find \(h'(x).\) [ \(h'(x)\) = \(x\over3\)]

Q6) h(x) = x + 10. Find h'(x). [ \(h'(x) \)= \({x -10}\over1\)]

Q6) f(x) =\( 2 x^ 2 -3\). Find f'(x). [ f'(x)= \( \sqrt[2]{{x +3}\over 2} \)]

Q7) \(g(x) =3{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over3\)]

Q7) f(x) = \(x\over 3\) + 2. Find f'(x). [ \(f'(x) \)= \(3(x -2)\)]

Q7) g(x) =\( 2 x^ 3 -4\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x +4}\over 2} \)]

Q8) \(g(x) =2{x}. \) Find \(g'(x).\) [ \(g'(x)\) = \(x\over2\)]

Q8) g(x) = x -4. Find g'(x). [ \(g'(x) \)= \({x +4}\over1\)]

Q8) g(x) =\( 8 x^ 2 + 6\). Find g'(x). [ g'(x)= \( \sqrt[2]{{x -6}\over 8} \)]

Q9) \(f(x) =9{x}. \) Find \(f'(x).\) [ \(f'(x)\) = \(x\over9\)]

Q9) f(x) = \(x\over 2\) -8. Find f'(x). [ \(f'(x) \)= \(2(x +8)\)]

Q9) g(x) =\( 2 x^ 3 + 4\). Find g'(x). [ g'(x)= \( \sqrt[3]{{x -4}\over 2} \)]

Q10) f(x) =x -4. Find f'(x). [ f'(x) = x +4]

Q10) g(x) = 8 x -7. Find g'(x). [ \(g'(x) \)= \({x +7}\over8\)]

Q10) f(x) =\(x^ 3 + 2\). Find f'(x). [ f'(x)= \( \sqrt[3]{x -2} \)]