Mr Daniels Maths
Simplifying Fractions

Set 1

Set 2

Set 3

Q1) \(10 \over 50\) = [ \(\frac{1}{5}\)]

Q1) \(16 \over 40\) = [ \(\frac{2}{5}\)]

Q1) \(10 \over 6\) = [ 1\(\frac{2}{3}\)]

Q2) \(5 \over 10\) = [ \(\frac{1}{2}\)]

Q2) \(72 \over 216\) = [ \(\frac{1}{3}\)]

Q2) \(10 \over 8\) = [ 1\(\frac{1}{4}\)]

Q3) \(6 \over 42\) = [ \(\frac{1}{7}\)]

Q3) \(81 \over 108\) = [ \(\frac{3}{4}\)]

Q3) \(30 \over 7\) = [ 4\(\frac{2}{7}\)]

Q4) \(4 \over 40\) = [ \(\frac{1}{10}\)]

Q4) \(16 \over 32\) = [ \(\frac{1}{2}\)]

Q4) \(18 \over 4\) = [ 4\(\frac{1}{2}\)]

Q5) \(4 \over 8\) = [ \(\frac{1}{2}\)]

Q5) \(120 \over 168\) = [ \(\frac{5}{7}\)]

Q5) \(16 \over 3\) = [ 5\(\frac{1}{3}\)]

Q6) \(3 \over 9\) = [ \(\frac{1}{3}\)]

Q6) \(84 \over 120\) = [ \(\frac{7}{10}\)]

Q6) \(4 \over 3\) = [ 1\(\frac{1}{3}\)]

Q7) \(5 \over 45\) = [ \(\frac{1}{9}\)]

Q7) \(12 \over 54\) = [ \(\frac{2}{9}\)]

Q7) \(54 \over 7\) = [ 7\(\frac{5}{7}\)]

Q8) \(3 \over 12\) = [ \(\frac{1}{4}\)]

Q8) \(120 \over 140\) = [ \(\frac{6}{7}\)]

Q8) \(10 \over 3\) = [ 3\(\frac{1}{3}\)]

Q9) \(7 \over 35\) = [ \(\frac{1}{5}\)]

Q9) \(18 \over 54\) = [ \(\frac{1}{3}\)]

Q9) \(20 \over 7\) = [ 2\(\frac{6}{7}\)]

Q10) \(9 \over 45\) = [ \(\frac{1}{5}\)]

Q10) \(8 \over 28\) = [ \(\frac{2}{7}\)]

Q10) \(56 \over 5\) = [ 11\(\frac{1}{5}\)]