Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \(11x + 4 = 92\) [ \( x = 8\)]

Q1) \(10(x -4) = 20\) [ x= \(6\)]

Q1) 8(3z -9) = 72 [ z = 6]

Q2) \( {x\over7}-4 = 3\) [ \(x= 49\)]

Q2) \(5(y + 2) = 60\) [ y= \(10\)]

Q2) 2(8z -6) = 52 [ z = 4]

Q3) \(13y + 10 = 75\) [ \( y = 5\)]

Q3) \(3(w + 6) = 36\) [ w= \(6\)]

Q3) 4(2y + 6) = 96 [ y = 9]

Q4) \(4w + 10 = 26\) [ \( w = 4\)]

Q4) \(3(z + 10) = 48\) [ z= \(6\)]

Q4) 6(2w + 8) = 72 [ w = 2]

Q5) \( {y\over2}+6 = 8\) [ \(y= 4\)]

Q5) \(6(y + 2) = 24\) [ y= \(2\)]

Q5) 3(10x -8) = 66 [ x = 3]

Q6) \( {y\over2}+9 = 11\) [ \(y= 4\)]

Q6) \(10(w + 10) = 200\) [ w= \(10\)]

Q6) 3(2z -9) = 33 [ z = 10]

Q7) \( {x\over9}-4 = 3\) [ \(x= 63\)]

Q7) \(7(z + 9) = 84\) [ z= \(3\)]

Q7) 3(9y -9) = 27 [ y = 2]

Q8) \(6y + 9 = 57\) [ \( y = 8\)]

Q8) \(10(y + 2) = 50\) [ y= \(3\)]

Q8) 2(5w + 4) = 78 [ w = 7]

Q9) \( {z\over3}+4 = 11\) [ \(z= 21\)]

Q9) \(5(w + 5) = 50\) [ w= \(5\)]

Q9) 5(7x + 2) = 80 [ x = 2]

Q10) \( {w\over4}+3 = 9\) [ \(w= 24\)]

Q10) \(10(w -4) = 30\) [ w= \(7\)]

Q10) 9(2y -7) = 99 [ y = 9]