Q1) $x + 10\over 5$ - $x + 8\over 7$ = [ $2 x + 30\over 35$ ]

Q1) $10\over x+ 5$ + $6\over x +3$ = [ $16 x + 60\over x^{2}+ 8 x +15$]

Q1) $10\over x+ 5$ - $4\over x -10$ = [ $6 x -120\over x^{2}-5x -50$]

Q2) $x + 5\over 2$ - $x + 10\over 9$ = [ $7 x + 25\over 18$ ]

Q2) $5\over x+ 3$ + $9\over x +3$ = [ $14 x + 42\over x^{2}+ 6 x +9$]

Q2) $6\over x+ 4$ + $8\over x -10$ = [ $14 x -28\over x^{2}-6x -40$]

Q3) $x + 10\over 5$ + $x + 7\over 5$ = [ $2 x + 17\over 5$ ]

Q3) $7\over x+ 6$ + $9\over x +7$ = [ $16 x + 103\over x^{2}+ 13 x +42$]

Q3) $10\over x+ 4$ + $4\over x -3$ = [ $14 x -14\over x^{2}+x -12$]

Q4) $x + 10\over 6$ + $x + 9\over 8$ = [ $7 x + 67\over 24$ ]

Q4) $8\over x+ 6$ - $4\over x +2$ = [ $4 x -8\over x^{2}+ 8 x +12$]

Q4) $10\over x+ 3$ + $8\over x -4$ = [ $18 x -16\over x^{2}-x -12$]

Q5) $x + 8\over 7$ + $x + 9\over 6$ = [ $13 x + 111\over 42$ ]

Q5) $7\over x+ 2$ - $5\over x +2$ = [ $2 x + 4\over x^{2}+ 4 x +4$]

Q5) $10\over x+ 6$ - $4\over x +3$ = [ $6 x + 6\over x^{2}+9x +18$]

Q6) $x + 3\over 2$ + $x + 10\over 6$ = [ $4 x + 19\over 6$ ]

Q6) $10\over x+ 2$ - $8\over x +3$ = [ $2 x + 14\over x^{2}+ 5 x +6$]

Q6) $10\over x+ 4$ - $7\over x -3$ = [ $3 x -58\over x^{2}+x -12$]

Q7) $x + 10\over 7$ + $x + 9\over 4$ = [ $11x + 103\over 28$ ]

Q7) $10\over x+ 4$ - $8\over x +4$ = [ $2 x + 8\over x^{2}+ 8 x +16$]

Q7) $10\over x+ 6$ - $8\over x +2$ = [ $2 x -28\over x^{2}+8x +12$]

Q8) $x + 3\over 2$ - $x + 9\over 7$ = [ $5 x + 3\over 14$ ]

Q8) $10\over x+ 3$ + $8\over x +2$ = [ $18 x + 44\over x^{2}+ 5 x +6$]

Q8) $10\over x+ 3$ + $3\over x -7$ = [ $13 x -61\over x^{2}-4x -21$]

Q9) $x + 9\over 6$ + $x + 8\over 5$ = [ $11x + 93\over 30$ ]

Q9) $9\over x+ 2$ - $3\over x +2$ = [ $6 x + 12\over x^{2}+ 4 x +4$]

Q9) $6\over x+ 5$ + $9\over x +2$ = [ $15 x + 57\over x^{2}+7x +10$]

Q10) $x + 4\over 3$ - $x + 9\over 7$ = [ $4 x + 1\over 21$ ]

Q10) $9\over x+ 4$ + $7\over x +6$ = [ $16 x + 82\over x^{2}+ 10 x +24$]

Q10) $10\over x+ 9$ - $2\over x -9$ = [ $8 x -108\over x^{2} -81$]