Mr Daniels Maths
Algebraic Fractions Addition and Subtraction

Set 1

Set 2

Set 3

Q1) \(x + 3\over 2\) + \(x + 6\over 3\) = [ \(5 x + 21\over 6\) ]

Q1) \(7\over x+ 5\) + \(8\over x +5\) = [ \(15 x + 75\over x^{2}+ 10 x +25 \)]

Q1) \(9\over x+ 7\) + \(7\over x -9\) = [ \(16 x -32\over x^{2}-2x -63 \)]

Q2) \(x + 10\over 4\) - \(x + 10\over 9\) = [ \(5 x + 50\over 36\) ]

Q2) \(9\over x+ 6\) - \(4\over x +2\) = [ \(5 x -6\over x^{2}+ 8 x +12 \)]

Q2) \(10\over x+ 3\) - \(7\over x +2\) = [ \(3 x -1\over x^{2}+5x +6 \)]

Q3) \(x + 8\over 3\) + \(x + 10\over 9\) = [ \(4 x + 34\over 9\) ]

Q3) \(9\over x+ 6\) - \(6\over x +3\) = [ \(3 x -9\over x^{2}+ 9 x +18 \)]

Q3) \(10\over x+ 2\) - \(4\over x -3\) = [ \(6 x -38\over x^{2}-x -6 \)]

Q4) \(x + 9\over 5\) - \(x + 9\over 7\) = [ \(2 x + 18\over 35\) ]

Q4) \(8\over x+ 5\) - \(4\over x +3\) = [ \(4 x + 4\over x^{2}+ 8 x +15 \)]

Q4) \(6\over x+ 2\) + \(6\over x -5\) = [ \(12 x -18\over x^{2}-3x -10 \)]

Q5) \(x + 5\over 4\) + \(x + 9\over 6\) = [ \(5 x + 33\over 12\) ]

Q5) \(7\over x+ 2\) - \(3\over x +2\) = [ \(4 x + 8\over x^{2}+ 4 x +4 \)]

Q5) \(4\over x+ 2\) + \(8\over x +6\) = [ \(12 x + 40\over x^{2}+8x +12 \)]

Q6) \(x + 5\over 3\) - \(x + 6\over 5\) = [ \(2 x + 7\over 15\) ]

Q6) \(9\over x+ 5\) - \(3\over x +2\) = [ \(6 x + 3\over x^{2}+ 7 x +10 \)]

Q6) \(10\over x+ 6\) - \(8\over x -6\) = [ \(2 x -108\over x^{2} -36 \)]

Q7) \(x + 8\over 7\) + \(x + 4\over 2\) = [ \(9 x + 44\over 14\) ]

Q7) \(10\over x+ 8\) + \(9\over x +3\) = [ \(19 x + 102\over x^{2}+ 11x +24 \)]

Q7) \(5\over x+ 4\) + \(5\over x +4\) = [ \(10 x + 40\over x^{2}+8x +16 \)]

Q8) \(x + 8\over 3\) - \(x + 6\over 5\) = [ \(2 x + 22\over 15\) ]

Q8) \(10\over x+ 7\) - \(7\over x +6\) = [ \(3 x + 11\over x^{2}+ 13 x +42 \)]

Q8) \(7\over x+ 2\) - \(3\over x -4\) = [ \(4 x -34\over x^{2}-2x -8 \)]

Q9) \(x + 6\over 2\) + \(x + 9\over 8\) = [ \(5 x + 33\over 8\) ]

Q9) \(6\over x+ 3\) + \(5\over x +4\) = [ \(11x + 39\over x^{2}+ 7 x +12 \)]

Q9) \(8\over x+ 7\) - \(3\over x -4\) = [ \(5 x -53\over x^{2}+3x -28 \)]

Q10) \(x + 7\over 6\) + \(x + 7\over 5\) = [ \(11x + 77\over 30\) ]

Q10) \(8\over x+ 4\) - \(6\over x +2\) = [ \(2 x -8\over x^{2}+ 6 x +8 \)]

Q10) \(9\over x+ 8\) + \(6\over x +5\) = [ \(15 x + 93\over x^{2}+13x +40 \)]