Q1) There are 2 red pencils, 6 are blue pencils, and 9 are purple pencils in a box
a) What is the probability of picking a red one?
b) What is the probability of picking a blue one?
c) What is the probability of picking a purple one?
[ a) P(red)=\(\frac{2}{17}\).
b) P(blue)=\(\frac{6}{17}\).
c) P(purple)=\(\frac{9}{17}\).
]

Q1) There were 5 green pencils ,and 2 yellow pencils in a tray . Two pencils were picked and not replaced. What was the probability they were both green ?
[ \(\frac{10}{21}\) ]

Q1) There are 6 yellow pencils ,and some red pencils in a packet . 7 extra red pencils were added. Two pencils were picked at random and not replaced. The probability they were both yellow was \(\frac{1}{14}\). How many red pencils were there to begin with ?
[ 8 ]

Q2) There are 6 purple beads ,and 6 yellow beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a yellow bead?
[ a) P(purple)=\(\frac{1}{2}\).
b) P(yellow)=\(\frac{1}{2}\).
]

Q2) There were 9 purple pens ,and 9 yellow pens in a packet . Two pens were picked and not replaced. What was the probability they were both purple ?
[ \(\frac{4}{17}\) ]

Q2) There were 7 green sweets ,and some blue sweets in a packet . Two sweets were picked at random and not replaced. The probability they were both green was \(\frac{21}{55}\). How many blue sweets were there ?
[ 4 ]

Q3) There are 9 red pencils, 7 are blue pencils, and 10 are yellow pencils in a bag
a) What is the probability of picking a red one?
b) What is the probability of picking a blue one?
c) What is the probability of picking a yellow one?
[ a) P(red)=\(\frac{9}{26}\).
b) P(blue)=\(\frac{7}{26}\).
c) P(yellow)=\(\frac{5}{13}\).
]

Q3) There were 8 blue sweets ,and 10 purple sweets in a tin . Two sweets were picked and not replaced. What was the probability they were both blue ?
[ \(\frac{28}{153}\) ]

Q3) There are 7 yellow sweets ,and some blue sweets in a bag . 8 extra blue sweets were added. Two sweets were picked at random and not replaced. The probability they were both yellow was \(\frac{1}{10}\). How many blue sweets were there to begin with ?
[ 6 ]

Q4) There are 2 red beads, 9 are green beads, and 2 are purple beads in a tin
a) What is the probability of picking a red one?
b) What is the probability of picking a green one?
c) What is the probability of picking a purple one?
[ a) P(red)=\(\frac{2}{13}\).
b) P(green)=\(\frac{9}{13}\).
c) P(purple)=\(\frac{2}{13}\).
]

Q4) There were 8 yellow beads ,and 7 red beads in a packet . Two beads were picked and not replaced. What was the probability they were both yellow ?
[ \(\frac{4}{15}\) ]

Q4) There are 7 yellow apples ,and some blue apples in a tin . 9 extra blue apples were added. Two apples were picked at random and not replaced. The probability they were both yellow was \(\frac{1}{10}\). How many blue apples were there to begin with ?
[ 5 ]

Q5) There are 8 red apples, 9 are purple apples, and 2 are yellow apples in a draw
a) What is the probability of picking a red one?
b) What is the probability of picking a purple one?
c) What is the probability of picking a yellow one?
[ a) P(red)=\(\frac{8}{19}\).
b) P(purple)=\(\frac{9}{19}\).
c) P(yellow)=\(\frac{2}{19}\).
]

Q5) There were 6 green sweets ,and 4 purple sweets in a draw . Two sweets were picked and not replaced. What was the probability they were both green ?
[ \(\frac{1}{3}\) ]

Q5) There are 10 purple beads ,and some red beads in a bag . 7 extra red beads were added. Two beads were picked at random and not replaced. The probability they were both purple was \(\frac{45}{253}\). How many red beads were there to begin with ?
[ 6 ]