Q1) There are 10 purple beads ,and 8 blue beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a blue bead?
[ a) P(purple)=\(\frac{5}{9}\).
b) P(blue)=\(\frac{4}{9}\).
]

Q1) There were 4 green apples ,and 10 yellow apples in a packet . Two apples were picked and not replaced. What was the probability they were both green ?
[ \(\frac{6}{91}\) ]

Q1) There are 5 purple beads ,and some yellow beads in a packet . 10 extra yellow beads were added. Two beads were picked at random and not replaced. The probability they were both purple was \(\frac{10}{171}\). How many yellow beads were there to begin with ?
[ 4 ]

Q2) There are 6 purple beads ,and 8 yellow beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a yellow bead?
[ a) P(purple)=\(\frac{3}{7}\).
b) P(yellow)=\(\frac{4}{7}\).
]

Q2) There were 9 green beads ,and 10 blue beads in a tin . Two beads were picked and not replaced. What was the probability they were both green ?
[ \(\frac{4}{19}\) ]

Q2) There were 5 yellow beads ,and some red beads in a box . Two beads were picked at random and not replaced. The probability they were both yellow was \(\frac{10}{21}\). How many red beads were there ?
[ 2 ]

Q3) There are 7 yellow beads ,and 10 red beads in a bag.
a) What is the probability of picking a yellow bead?
b) What is the probability of picking a red bead?
[ a) P(yellow)=\(\frac{7}{17}\).
b) P(red)=\(\frac{10}{17}\).
]

Q3) There were 4 purple pencils ,and 9 red pencils in a packet . Two pencils were picked and not replaced. What was the probability they were both purple ?
[ \(\frac{1}{13}\) ]

Q3) There were 7 yellow apples ,and some red apples in a box . Two apples were picked at random and not replaced. The probability they were both yellow was \(\frac{3}{13}\). How many red apples were there ?
[ 7 ]

Q4) There are 5 red beads ,and 4 yellow beads in a bag.
a) What is the probability of picking a red bead?
b) What is the probability of picking a yellow bead?
[ a) P(red)=\(\frac{5}{9}\).
b) P(yellow)=\(\frac{4}{9}\).
]

Q4) There were 10 red pencils ,and 8 blue pencils in a packet . Two pencils were picked and not replaced. What was the probability they were both red ?
[ \(\frac{5}{17}\) ]

Q4) There were 7 blue pencils ,and some green pencils in a bag . Two pencils were picked at random and not replaced. The probability they were both blue was \(\frac{7}{12}\). How many green pencils were there ?
[ 2 ]

Q5) There are 2 purple beads ,and 7 blue beads in a bag.
a) What is the probability of picking a purple bead?
b) What is the probability of picking a blue bead?
[ a) P(purple)=\(\frac{2}{9}\).
b) P(blue)=\(\frac{7}{9}\).
]

Q5) There were 5 green apples ,and 8 red apples in a tray . Two apples were picked and not replaced. What was the probability they were both green ?
[ \(\frac{5}{39}\) ]

Q5) There are 4 yellow pencils ,and some purple pencils in a bag . 8 extra purple pencils were added. Two pencils were picked at random and not replaced. The probability they were both yellow was \(\frac{1}{20}\). How many purple pencils were there to begin with ?
[ 4 ]