Q1) There are 10 yellowapples, 10 are blue apples, and 8 are green apples in a tray
a) What is the probability of picking a yellow one?
b) What is the probability of picking a blue one?
c) What is the probability of picking a green one?
a) P(yellow)=\(\frac{5}{14}\).
b) P(blue)=\(\frac{5}{14}\).
c) P(green)=\(\frac{2}{7}\).
a) What is the probability of picking a yellow one?
b) What is the probability of picking a blue one?
c) What is the probability of picking a green one?
a) P(yellow)=\(\frac{5}{14}\).
b) P(blue)=\(\frac{5}{14}\).
c) P(green)=\(\frac{2}{7}\).
Q1) There were 4 blue sweets ,and 3 red sweets in a tray . Two sweets were picked and not replaced. What was the probability they were both blue ?
\(\frac{2}{7}\)
\(\frac{2}{7}\)
Q1) There are 4 yellow sweets ,and some purple sweets in a tray . 10 extra purple sweets were added. Two sweets were picked at random and not replaced. The probability they were both yellow was \(\frac{2}{77}\). How many purple sweets were there to begin with ?
8
8
Q2) There are 10 purplesweets, 4 are green sweets, and 5 are red sweets in a draw
a) What is the probability of picking a purple one?
b) What is the probability of picking a green one?
c) What is the probability of picking a red one?
a) P(purple)=\(\frac{10}{19}\).
b) P(green)=\(\frac{4}{19}\).
c) P(red)=\(\frac{5}{19}\).
a) What is the probability of picking a purple one?
b) What is the probability of picking a green one?
c) What is the probability of picking a red one?
a) P(purple)=\(\frac{10}{19}\).
b) P(green)=\(\frac{4}{19}\).
c) P(red)=\(\frac{5}{19}\).
Q2) There were 7 green beads ,and 10 purple beads in a tray . Two beads were picked and not replaced. What was the probability they were both green ?
\(\frac{21}{136}\)
\(\frac{21}{136}\)
Q2) There were 5 yellow sweets ,and some purple sweets in a draw . Two sweets were picked at random and not replaced. The probability they were both yellow was \(\frac{5}{33}\). How many purple sweets were there ?
7
7
Q3) There are 5 greensweets, 8 are red sweets, and 9 are purple sweets in a draw
a) What is the probability of picking a green one?
b) What is the probability of picking a red one?
c) What is the probability of picking a purple one?
a) P(green)=\(\frac{5}{22}\).
b) P(red)=\(\frac{4}{11}\).
c) P(purple)=\(\frac{9}{22}\).
a) What is the probability of picking a green one?
b) What is the probability of picking a red one?
c) What is the probability of picking a purple one?
a) P(green)=\(\frac{5}{22}\).
b) P(red)=\(\frac{4}{11}\).
c) P(purple)=\(\frac{9}{22}\).
Q3) There were 4 green pencils ,and 8 red pencils in a box . Two pencils were picked and not replaced. What was the probability they were both green ?
\(\frac{1}{11}\)
\(\frac{1}{11}\)
Q3) There were 9 green pens ,and some purple pens in a tray . Two pens were picked at random and not replaced. The probability they were both green was \(\frac{36}{91}\). How many purple pens were there ?
5
5
Q4) There are 4 green beads ,and 2 red beads in a bag.
a) What is the probability of picking a green bead?
b) What is the probability of picking a red bead?
a) P(green)=\(\frac{2}{3}\).
b) P(red)=\(\frac{1}{3}\).
a) What is the probability of picking a green bead?
b) What is the probability of picking a red bead?
a) P(green)=\(\frac{2}{3}\).
b) P(red)=\(\frac{1}{3}\).
Q4) There were 5 blue sweets ,and 9 purple sweets in a tin . Two sweets were picked and not replaced. What was the probability they were both blue ?
\(\frac{10}{91}\)
\(\frac{10}{91}\)
Q4) There are 9 green pens ,and some blue pens in a box . 5 extra blue pens were added. Two pens were picked at random and not replaced. The probability they were both green was \(\frac{3}{10}\). How many blue pens were there to begin with ?
2
2
Q5) There are 3 blue beads ,and 2 yellow beads in a bag.
a) What is the probability of picking a blue bead?
b) What is the probability of picking a yellow bead?
a) P(blue)=\(\frac{3}{5}\).
b) P(yellow)=\(\frac{2}{5}\).
a) What is the probability of picking a blue bead?
b) What is the probability of picking a yellow bead?
a) P(blue)=\(\frac{3}{5}\).
b) P(yellow)=\(\frac{2}{5}\).
Q5) There were 4 red pens ,and 10 yellow pens in a draw . Two pens were picked and not replaced. What was the probability they were both red ?
\(\frac{6}{91}\)
\(\frac{6}{91}\)
Q5) There were 8 purple apples ,and some blue apples in a bag . Two apples were picked at random and not replaced. The probability they were both purple was \(\frac{7}{30}\). How many blue apples were there ?
8
8