Q1) There are 9 green beads ,and 3 purple beads in a bag.
a) What is the probability of picking a green bead?
b) What is the probability of picking a purple bead?
[ a) P(green)=$\frac{3}{4}$.
b) P(purple)=$\frac{1}{4}$.
]

Q1) There were 4 blue pencils ,and 6 red pencils in a draw . Two pencils were picked and not replaced. What was the probability they were both blue ?
[ $\frac{2}{15}$ ]

Q1) There are 8 green sweets ,and some blue sweets in a tray . 10 extra blue sweets were added. Two sweets were picked at random and not replaced. The probability they were both green was $\frac{7}{69}$. How many blue sweets were there to begin with ?
[ 6 ]

Q2) There are 5 green beads ,and 6 purple beads in a bag.
a) What is the probability of picking a green bead?
b) What is the probability of picking a purple bead?
[ a) P(green)=$\frac{5}{11}$.
b) P(purple)=$\frac{6}{11}$.
]

Q2) There were 9 green pencils ,and 9 purple pencils in a packet . Two pencils were picked and not replaced. What was the probability they were both green ?
[ $\frac{4}{17}$ ]

Q2) There were 5 purple apples ,and some red apples in a draw . Two apples were picked at random and not replaced. The probability they were both purple was $\frac{2}{21}$. How many red apples were there ?
[ 10 ]

Q3) There are 2 purplebeads, 9 are green beads, and 10 are red beads in a draw
a) What is the probability of picking a purple one?
b) What is the probability of picking a green one?
c) What is the probability of picking a red one?
[ a) P(purple)=$\frac{2}{21}$.
b) P(green)=$\frac{3}{7}$.
c) P(red)=$\frac{10}{21}$.
]

Q3) There were 4 purple beads ,and 5 green beads in a tray . Two beads were picked and not replaced. What was the probability they were both purple ?
[ $\frac{1}{6}$ ]

Q3) There are 7 green apples ,and some purple apples in a tin . 8 extra purple apples were added. Two apples were picked at random and not replaced. The probability they were both green was $\frac{7}{100}$. How many purple apples were there to begin with ?
[ 10 ]

Q4) There are 8 yellow beads ,and 2 blue beads in a bag.
a) What is the probability of picking a yellow bead?
b) What is the probability of picking a blue bead?
[ a) P(yellow)=$\frac{4}{5}$.
b) P(blue)=$\frac{1}{5}$.
]

Q4) There were 7 blue pencils ,and 8 red pencils in a tray . Two pencils were picked and not replaced. What was the probability they were both blue ?
[ $\frac{1}{5}$ ]

Q4) There were 7 blue sweets ,and some green sweets in a bag . Two sweets were picked at random and not replaced. The probability they were both blue was $\frac{21}{136}$. How many green sweets were there ?
[ 10 ]

Q5) There are 2 greenbeads, 9 are blue beads, and 7 are red beads in a tin
a) What is the probability of picking a green one?
b) What is the probability of picking a blue one?
c) What is the probability of picking a red one?
[ a) P(green)=$\frac{1}{9}$.
b) P(blue)=$\frac{1}{2}$.
c) P(red)=$\frac{7}{18}$.
]

Q5) There were 6 yellow pencils ,and 7 blue pencils in a box . Two pencils were picked and not replaced. What was the probability they were both yellow ?
[ $\frac{5}{26}$ ]

Q5) There are 7 yellow pencils ,and some blue pencils in a tin . 7 extra blue pencils were added. Two pencils were picked at random and not replaced. The probability they were both yellow was $\frac{7}{57}$. How many blue pencils were there to begin with ?
[ 5 ]