Q1) \(x + 2\over 5\) ÷ \(6 \over {x + 6}\) = [ \(x^2 + 8 x + 12\over 30\) ]

Q1) \(x + 4\over 9\) ÷ \({ x + 9} \over 2 \) = [ \(2( x + 4) \over 9 ( x + 9)\) ]

Q1) \(x + 7\over 7\) x \(x + 10\over x + 7\) = [ \(x + 10\over 7\) ]

Q2) \(x + 8\over 5\) ÷ \(5 \over {x + 10}\) = [ \(x^2 + 18 x + 80\over 25\) ]

Q2) \(x + 9\over 8\) x \(5 \over{ x + 8}\) = [ \(5( x + 9) \over 8 ( x + 8)\) ]

Q2) \(x + 7\over 8\) x \(x + 4\over x + 7\) = [ \(x + 4\over 8\) ]

Q3) \(x + 1\over 10\) x \(x + 8\over 10\) = [ \(x^2 + 9 x + 8\over 100\) ]

Q3) \(x + 4\over 2\) ÷ \({ x + 9} \over 1 \) = [ \(1( x + 4) \over 2 ( x + 9)\) ]

Q3) \(x + 7\over 3\) ÷ \( x + 7\over x + 7\) = [ \(x + 7\over 3\) ]

Q4) \(x + 1\over 2\) ÷ \(3 \over {x + 3}\) = [ \(x^2 + 4 x + 3\over 6\) ]

Q4) \(x + 1\over 2\) ÷ \({ x + 8} \over 3 \) = [ \(3( x + 1) \over 2 ( x + 8)\) ]

Q4) \(x + 3\over 8\) x \(x + 6\over x + 3\) = [ \(x + 6\over 8\) ]

Q5) \(x + 8\over 9\) x \(x + 1\over 4\) = [ \(x^2 + 9 x + 8\over 36\) ]

Q5) \(x + 2\over 1\) x \(3 \over{ x + 5}\) = [ \(3( x + 2) \over( x + 5)\) ]

Q5) \(x + 1\over 9\) x \(x + 8\over x + 1\) = [ \(x + 8\over 9\) ]

Q6) \(x + 4\over 7\) ÷ \(7 \over {x + 8}\) = [ \(x^2 + 12 x + 32\over 49\) ]

Q6) \(x + 4\over 4\) x \(7 \over{ x + 9}\) = [ \(7( x + 4) \over 4 ( x + 9)\) ]

Q6) \(x + 8\over 3\) ÷ \( x + 8\over x + 7\) = [ \(x + 7\over 3\) ]

Q7) \(x + 5\over 7\) ÷ \(6 \over {x + 9}\) = [ \(x^2 + 14 x + 45\over 42\) ]

Q7) \(x + 10\over 2\) ÷ \({ x + 6} \over 3 \) = [ \(3( x + 10) \over 2 ( x + 6)\) ]

Q7) \(x + 8\over 10\) x \(x + 7\over x + 8\) = [ \(x + 7\over 10\) ]

Q8) \(x + 1\over 10\) ÷ \(3 \over {x + 5}\) = [ \(x^2 + 6 x + 5\over 30\) ]

Q8) \(x + 3\over 2\) x \(5 \over{ x + 8}\) = [ \(5( x + 3) \over 2 ( x + 8)\) ]

Q8) \(x + 1\over 4\) ÷ \( x + 1\over x + 2\) = [ \(x + 2\over 4\) ]

Q9) \(x + 3\over 7\) ÷ \(10 \over {x + 6}\) = [ \(x^2 + 9 x + 18\over 70\) ]

Q9) \(x + 3\over 1\) ÷ \({ x + 9} \over 1 \) = [ \(1( x + 3) \over( x + 9)\) ]

Q9) \(x + 4\over 3\) ÷ \( x + 4\over x + 7\) = [ \(x + 7\over 3\) ]

Q10) \(x + 4\over 5\) x \(x + 2\over 2\) = [ \(x^2 + 6 x + 8\over 10\) ]

Q10) \(x + 4\over 1\) ÷ \({ x + 3} \over 1 \) = [ \(1( x + 4) \over( x + 3)\) ]

Q10) \(x + 3\over 9\) ÷ \( x + 3\over x + 9\) = [ \(x + 9\over 9\) ]