Q1) \(x + 10\over 9\) x \(x + 3\over 9\) = [ \(x^2 + 13 x + 30\over 81\) ]

Q1) \(x + 8\over 4\) ÷ \({ x + 2} \over 5 \) = [ \(5( x + 8) \over 4 ( x + 2)\) ]

Q1) \(x + 2\over 9\) ÷ \( x + 2\over x + 6\) = [ \(x + 6\over 9\) ]

Q2) \(x + 8\over 4\) x \(x + 6\over 5\) = [ \(x^2 + 14 x + 48\over 20\) ]

Q2) \(x + 9\over 2\) ÷ \({ x + 3} \over 9 \) = [ \(9( x + 9) \over 2 ( x + 3)\) ]

Q2) \(x + 8\over 4\) ÷ \( x + 8\over x + 5\) = [ \(x + 5\over 4\) ]

Q3) \(x + 2\over 5\) x \(x + 7\over 6\) = [ \(x^2 + 9 x + 14\over 30\) ]

Q3) \(x + 3\over 1\) x \(2 \over{ x + 6}\) = [ \(2( x + 3) \over( x + 6)\) ]

Q3) \(x + 1\over 8\) ÷ \( x + 1\over x + 3\) = [ \(x + 3\over 8\) ]

Q4) \(x + 3\over 8\) x \(x + 8\over 4\) = [ \(x^2 + 11x + 24\over 32\) ]

Q4) \(x + 10\over 1\) x \(2 \over{ x + 9}\) = [ \(2( x + 10) \over( x + 9)\) ]

Q4) \(x + 6\over 7\) ÷ \( x + 6\over x + 6\) = [ \(x + 6\over 7\) ]

Q5) \(x + 7\over 5\) x \(x + 6\over 10\) = [ \(x^2 + 13 x + 42\over 50\) ]

Q5) \(x + 5\over 4\) ÷ \({ x + 1} \over 3 \) = [ \(3( x + 5) \over 4 ( x + 1)\) ]

Q5) \(x + 4\over 2\) ÷ \( x + 4\over x + 5\) = [ \(x + 5\over 2\) ]

Q6) \(x + 3\over 10\) x \(x + 9\over 6\) = [ \(x^2 + 12 x + 27\over 60\) ]

Q6) \(x + 1\over 4\) x \(3 \over{ x + 8}\) = [ \(3( x + 1) \over 4 ( x + 8)\) ]

Q6) \(x + 7\over 9\) ÷ \( x + 7\over x + 1\) = [ \(x + 1\over 9\) ]

Q7) \(x + 1\over 3\) ÷ \(2 \over {x + 1}\) = [ \(x^2 + 2 x + 1\over 6\) ]

Q7) \(x + 4\over 1\) x \(2 \over{ x + 1}\) = [ \(2( x + 4) \over( x + 1)\) ]

Q7) \(x + 9\over 9\) x \(x + 2\over x + 9\) = [ \(x + 2\over 9\) ]

Q8) \(x + 5\over 6\) x \(x + 1\over 10\) = [ \(x^2 + 6 x + 5\over 60\) ]

Q8) \(x + 1\over 2\) x \(1 \over{ x + 5}\) = [ \(1( x + 1) \over 2 ( x + 5)\) ]

Q8) \(x + 5\over 9\) x \(x + 10\over x + 5\) = [ \(x + 10\over 9\) ]

Q9) \(x + 1\over 2\) x \(x + 7\over 6\) = [ \(x^2 + 8 x + 7\over 12\) ]

Q9) \(x + 1\over 4\) x \(7 \over{ x + 6}\) = [ \(7( x + 1) \over 4 ( x + 6)\) ]

Q9) \(x + 7\over 9\) x \(x + 9\over x + 7\) = [ \(x + 9\over 9\) ]

Q10) \(x + 8\over 9\) x \(x + 7\over 7\) = [ \(x^2 + 15 x + 56\over 63\) ]

Q10) \(x + 6\over 5\) x \(6 \over{ x + 4}\) = [ \(6( x + 6) \over 5 ( x + 4)\) ]

Q10) \(x + 10\over 4\) x \(x + 7\over x + 10\) = [ \(x + 7\over 4\) ]