Q1) \(x + 1\over 7\) ÷ \(10 \over {x + 4}\) = [ \(x^2 + 5 x + 4\over 70\) ]

Q1) \(x + 4\over 1\) ÷ \({ x + 1} \over 1 \) = [ \(1( x + 4) \over( x + 1)\) ]

Q1) \(x + 6\over 4\) ÷ \( x + 6\over x + 10\) = [ \(x + 10\over 4\) ]

Q2) \(x + 7\over 5\) x \(x + 1\over 4\) = [ \(x^2 + 8 x + 7\over 20\) ]

Q2) \(x + 5\over 3\) x \(5 \over{ x + 1}\) = [ \(5( x + 5) \over 3 ( x + 1)\) ]

Q2) \(x + 1\over 9\) x \(x + 3\over x + 1\) = [ \(x + 3\over 9\) ]

Q3) \(x + 1\over 3\) x \(x + 2\over 3\) = [ \(x^2 + 3 x + 2\over 9\) ]

Q3) \(x + 6\over 9\) x \(8 \over{ x + 10}\) = [ \(8( x + 6) \over 9 ( x + 10)\) ]

Q3) \(x + 4\over 4\) x \(x + 4\over x + 4\) = [ \(x + 4\over 4\) ]

Q4) \(x + 5\over 10\) x \(x + 3\over 4\) = [ \(x^2 + 8 x + 15\over 40\) ]

Q4) \(x + 5\over 3\) ÷ \({ x + 4} \over 4 \) = [ \(4( x + 5) \over 3 ( x + 4)\) ]

Q4) \(x + 6\over 9\) ÷ \( x + 6\over x + 3\) = [ \(x + 3\over 9\) ]

Q5) \(x + 5\over 4\) ÷ \(5 \over {x + 6}\) = [ \(x^2 + 11x + 30\over 20\) ]

Q5) \(x + 9\over 5\) ÷ \({ x + 3} \over 7 \) = [ \(7( x + 9) \over 5 ( x + 3)\) ]

Q5) \(x + 4\over 7\) x \(x + 10\over x + 4\) = [ \(x + 10\over 7\) ]

Q6) \(x + 5\over 7\) ÷ \(6 \over {x + 1}\) = [ \(x^2 + 6 x + 5\over 42\) ]

Q6) \(x + 9\over 1\) ÷ \({ x + 6} \over 1 \) = [ \(1( x + 9) \over( x + 6)\) ]

Q6) \(x + 5\over 8\) ÷ \( x + 5\over x + 4\) = [ \(x + 4\over 8\) ]

Q7) \(x + 6\over 10\) ÷ \(2 \over {x + 4}\) = [ \(x^2 + 10 x + 24\over 20\) ]

Q7) \(x + 6\over 3\) ÷ \({ x + 2} \over 5 \) = [ \(5( x + 6) \over 3 ( x + 2)\) ]

Q7) \(x + 8\over 6\) x \(x + 4\over x + 8\) = [ \(x + 4\over 6\) ]

Q8) \(x + 3\over 4\) ÷ \(7 \over {x + 1}\) = [ \(x^2 + 4 x + 3\over 28\) ]

Q8) \(x + 9\over 10\) ÷ \({ x + 2} \over 3 \) = [ \(3( x + 9) \over 10 ( x + 2)\) ]

Q8) \(x + 10\over 2\) x \(x + 3\over x + 10\) = [ \(x + 3\over 2\) ]

Q9) \(x + 2\over 5\) ÷ \(5 \over {x + 4}\) = [ \(x^2 + 6 x + 8\over 25\) ]

Q9) \(x + 7\over 8\) ÷ \({ x + 10} \over 5 \) = [ \(5( x + 7) \over 8 ( x + 10)\) ]

Q9) \(x + 5\over 9\) ÷ \( x + 5\over x + 7\) = [ \(x + 7\over 9\) ]

Q10) \(x + 2\over 10\) x \(x + 7\over 10\) = [ \(x^2 + 9 x + 14\over 100\) ]

Q10) \(x + 9\over 3\) ÷ \({ x + 5} \over 2 \) = [ \(2( x + 9) \over 3 ( x + 5)\) ]

Q10) \(x + 6\over 7\) x \(x + 1\over x + 6\) = [ \(x + 1\over 7\) ]