Mr Daniels Maths
Algebraic Fractions Simplification

Set 1

Set 2

Set 3

Q1) \({x+2\over{x^2 +4x+4}}\) = [ \(1\over{x+2}\) ]

Q1) \({x^2 -16}\over{x+4}\) = [ \(x-4\) ]

Q1) \({4x^2 -25x+25}\over{x-5}\) = [ \(4x-5\) ]

Q2) \({x+4\over{x^2 +10x+24}}\) = [ \(1\over{x+6}\) ]

Q2) \({x-2}\over{x^2 -4}\) = [ \(1\over{x+2}\) ]

Q2) \({2x^2 -2x-4}\over{x-2}\) = [ \(2x+2\) ]

Q3) \({x+7\over{x^2 +5x-14}}\) = [ \(1\over{x-2}\) ]

Q3) \({x-7}\over{x^2 -49}\) = [ \(1\over{x+7}\) ]

Q3) \({2x^2 -7x-30}\over{x-6}\) = [ \(2x+5\) ]

Q4) \({x^2 -x-6}\over{x+2}\) = [ \(x-3\) ]

Q4) \({x^2 -49}\over{x-7}\) = [ \(x+7\) ]

Q4) \({4x^2 -10x+4}\over{x-2}\) = [ \(4x-2\) ]

Q5) \({x^2 +7x+12}\over{x+3}\) = [ \(x+4\) ]

Q5) \({x+3}\over{x^2 -9}\) = [ \(1\over{x-3}\) ]

Q5) \({2x^2 -11x+12}\over{x-4}\) = [ \(2x-3\) ]

Q6) \({x+5\over{x^2 +7x+10}}\) = [ \(1\over{x+2}\) ]

Q6) \({x^2 -4}\over{x-2}\) = [ \(x+2\) ]

Q6) \({4x^2 +21x+20}\over{x+4}\) = [ \(4x+5\) ]

Q7) \({x+2\over{x^2 -x-6}}\) = [ \(1\over{x-3}\) ]

Q7) \({x^2 -25}\over{x+5}\) = [ \(x-5\) ]

Q7) \({4x^2 +19x+12}\over{x+4}\) = [ \(4x+3\) ]

Q8) \({x^2 -7x+12}\over{x-4}\) = [ \(x-3\) ]

Q8) \({x+10}\over{x^2 -100}\) = [ \(1\over{x-10}\) ]

Q8) \({2x^2 +18x+36}\over{x+6}\) = [ \(2x+6\) ]

Q9) \({x+4\over{x^2 +7x+12}}\) = [ \(1\over{x+3}\) ]

Q9) \({x+9}\over{x^2 -81}\) = [ \(1\over{x-9}\) ]

Q9) \({2x^2 +2x-24}\over{x+4}\) = [ \(2x-6\) ]

Q10) \({x^2 +6x+8}\over{x+4}\) = [ \(x+2\) ]

Q10) \({x-8}\over{x^2 -64}\) = [ \(1\over{x+8}\) ]

Q10) \({2x^2 +8x-10}\over{x+5}\) = [ \(2x-2\) ]