Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q1) 7\(\frac{4}{5}\)= [ \(39\over5\) ]

Q1) 12\(\frac{4}{9}\)= [ \(112\over9\) ]

Q2) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q2) 6\(\frac{4}{5}\)= [ \(34\over5\) ]

Q2) 4\(\frac{5}{11}\)= [ \(49\over11\) ]

Q3) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q3) 12\(\frac{3}{5}\)= [ \(63\over5\) ]

Q3) 12\(\frac{8}{11}\)= [ \(140\over11\) ]

Q4) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q4) 6\(\frac{5}{6}\)= [ \(41\over6\) ]

Q4) 11\(\frac{1}{12}\)= [ \(133\over12\) ]

Q5) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q5) 8\(\frac{1}{5}\)= [ \(41\over5\) ]

Q5) 15\(\frac{5}{9}\)= [ \(140\over9\) ]

Q6) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q6) 4\(\frac{1}{5}\)= [ \(21\over5\) ]

Q6) 11\(\frac{3}{8}\)= [ \(91\over8\) ]

Q7) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q7) 7\(\frac{1}{6}\)= [ \(43\over6\) ]

Q7) 13\(\frac{2}{9}\)= [ \(119\over9\) ]

Q8) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q8) 9\(\frac{4}{5}\)= [ \(49\over5\) ]

Q8) 9\(\frac{5}{8}\)= [ \(77\over8\) ]

Q9) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q9) 4\(\frac{1}{6}\)= [ \(25\over6\) ]

Q9) 13\(\frac{3}{10}\)= [ \(133\over10\) ]

Q10) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q10) 13\(\frac{2}{5}\)= [ \(67\over5\) ]

Q10) 13\(\frac{1}{8}\)= [ \(105\over8\) ]