Mr Daniels Maths
Conversions: Mixed to Improper fractions

Set 1

Set 2

Set 3

Q1) 4\(\frac{2}{3}\)= [ \(14\over3\) ]

Q1) 8\(\frac{5}{6}\)= [ \(53\over6\) ]

Q1) 3\(\frac{1}{9}\)= [ \(28\over9\) ]

Q2) 5\(\frac{1}{3}\)= [ \(16\over3\) ]

Q2) 4\(\frac{5}{6}\)= [ \(29\over6\) ]

Q2) 8\(\frac{10}{11}\)= [ \(98\over11\) ]

Q3) 6\(\frac{1}{2}\)= [ \(13\over2\) ]

Q3) 5\(\frac{1}{6}\)= [ \(31\over6\) ]

Q3) 7\(\frac{7}{12}\)= [ \(91\over12\) ]

Q4) 6\(\frac{2}{3}\)= [ \(20\over3\) ]

Q4) 10\(\frac{1}{6}\)= [ \(61\over6\) ]

Q4) 9\(\frac{5}{8}\)= [ \(77\over8\) ]

Q5) 5\(\frac{2}{3}\)= [ \(17\over3\) ]

Q5) 5\(\frac{5}{6}\)= [ \(35\over6\) ]

Q5) 9\(\frac{11}{12}\)= [ \(119\over12\) ]

Q6) 4\(\frac{1}{3}\)= [ \(13\over3\) ]

Q6) 7\(\frac{1}{6}\)= [ \(43\over6\) ]

Q6) 12\(\frac{1}{11}\)= [ \(133\over11\) ]

Q7) 3\(\frac{1}{3}\)= [ \(10\over3\) ]

Q7) 12\(\frac{3}{5}\)= [ \(63\over5\) ]

Q7) 13\(\frac{3}{10}\)= [ \(133\over10\) ]

Q8) 6\(\frac{1}{3}\)= [ \(19\over3\) ]

Q8) 13\(\frac{2}{5}\)= [ \(67\over5\) ]

Q8) 4\(\frac{9}{10}\)= [ \(49\over10\) ]

Q9) 5\(\frac{1}{2}\)= [ \(11\over2\) ]

Q9) 11\(\frac{1}{6}\)= [ \(67\over6\) ]

Q9) 10\(\frac{1}{9}\)= [ \(91\over9\) ]

Q10) 3\(\frac{2}{3}\)= [ \(11\over3\) ]

Q10) 7\(\frac{3}{5}\)= [ \(38\over5\) ]

Q10) 8\(\frac{5}{9}\)= [ \(77\over9\) ]