Mr Daniels Maths
Difference of two squares

Set 1

Set 2

Set 3

Q1) Expand \((x+10)(x-10)\) = [ \(x^2 - 100\)]

Q1) Factorise \(x^2 - 16\)= [ \((x+4)(x-4)\)]

Q1) Factorise \(81x^2-25\)= [ \((9x + 5)(9x - 5)\)]

Q2) Expand \((x+6)(x-6)\) = [ \(x^2 - 36\)]

Q2) Factorise \(x^2 - 4\)= [ \((x+2)(x-2)\)]

Q2) Factorise \(64x^2-36\)= [ \((8x + 6)(8x - 6)\)]

Q3) Expand \((x+4)(x-4)\) = [ \(x^2 - 16\)]

Q3) Factorise \(x^2 - 25\)= [ \((x+5)(x-5)\)]

Q3) Factorise \(4x^2-16\)= [ \((2x + 4)(2x - 4)\)]

Q4) Expand \((x+5)(x-5)\) = [ \(x^2 - 25\)]

Q4) Factorise \(x^2 - 196\)= [ \((x+14)(x-14)\)]

Q4) Factorise \(9x^2-1\)= [ \((3x + 1)(3x - 1)\)]

Q5) Expand \((x+3)(x-3)\) = [ \(x^2 - 9\)]

Q5) Factorise \(x^2 - 9\)= [ \((x+3)(x-3)\)]

Q5) Factorise \(100x^2-4\)= [ \((10x + 2)(10x - 2)\)]

Q6) Expand \((x+8)(x-8)\) = [ \(x^2 - 64\)]

Q6) Factorise \(x^2 - 49\)= [ \((x+7)(x-7)\)]

Q6) Factorise \(25x^2-1\)= [ \((5x + 1)(5x - 1)\)]

Q7) Expand \((x+1)(x-1)\) = [ \(x^2 - 1\)]

Q7) Factorise \(x^2 - 361\)= [ \((x+19)(x-19)\)]

Q7) Factorise \(81x^2-1\)= [ \((9x + 1)(9x - 1)\)]

Q8) Expand \((x+2)(x-2)\) = [ \(x^2 - 4\)]

Q8) Factorise \(x^2 - 121\)= [ \((x+11)(x-11)\)]

Q8) Factorise \(64x^2-25\)= [ \((8x + 5)(8x - 5)\)]

Q9) Expand \((x+7)(x-7)\) = [ \(x^2 - 49\)]

Q9) Factorise \(x^2 - 289\)= [ \((x+17)(x-17)\)]

Q9) Factorise \(9x^2-16\)= [ \((3x + 4)(3x - 4)\)]

Q10) Expand \((x+9)(x-9)\) = [ \(x^2 - 81\)]

Q10) Factorise \(x^2 - 100\)= [ \((x+10)(x-10)\)]

Q10) Factorise \(81x^2-36\)= [ \((9x + 6)(9x - 6)\)]