Mr Daniels Maths
Fraction Addition and Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{3}{10}\) + \(\frac{4}{7}\) = [ \(\frac{61}{70}\)]

Q1) \(\frac{5}{6}\) - \(\frac{1}{2}\) = [ \(\frac{1}{3}\)]

Q1) 1\(\frac{2}{3}\) - 1\(\frac{4}{7}\) = [ \(\frac{2}{21}\)]

Q2) \(\frac{3}{10}\) + \(\frac{3}{8}\) = [ \(\frac{27}{40}\)]

Q2) \(\frac{3}{4}\) - \(\frac{3}{10}\) = [ \(\frac{9}{20}\)]

Q2) 3\(\frac{1}{2}\) - 1\(\frac{1}{2}\) = [ 2]

Q3) \(\frac{1}{5}\) + \(\frac{1}{2}\) = [ \(\frac{7}{10}\)]

Q3) \(\frac{3}{4}\) - \(\frac{3}{8}\) = [ \(\frac{3}{8}\)]

Q3) 2\(\frac{3}{5}\) - 1\(\frac{5}{9}\) = [ 1\(\frac{2}{45}\)]

Q4) \(\frac{3}{8}\) + \(\frac{1}{4}\) = [ \(\frac{5}{8}\)]

Q4) \(\frac{3}{4}\) - \(\frac{2}{3}\) = [ \(\frac{1}{12}\)]

Q4) 1\(\frac{1}{2}\) + \(\frac{3}{7}\) = [ 1\(\frac{13}{14}\)]

Q5) \(\frac{4}{7}\) + \(\frac{2}{5}\) = [ \(\frac{34}{35}\)]

Q5) \(\frac{3}{5}\) - \(\frac{2}{5}\) = [ \(\frac{1}{5}\)]

Q5) 4\(\frac{1}{2}\) + \(\frac{9}{10}\) = [ 5\(\frac{2}{5}\)]

Q6) \(\frac{2}{7}\) + \(\frac{4}{9}\) = [ \(\frac{46}{63}\)]

Q6) \(\frac{1}{2}\) - \(\frac{3}{7}\) = [ \(\frac{1}{14}\)]

Q6) 4\(\frac{1}{2}\) + \(\frac{2}{3}\) = [ 5\(\frac{1}{6}\)]

Q7) \(\frac{3}{7}\) + \(\frac{1}{2}\) = [ \(\frac{13}{14}\)]

Q7) \(\frac{3}{5}\) - \(\frac{1}{2}\) = [ \(\frac{1}{10}\)]

Q7) 2\(\frac{2}{3}\) + \(\frac{2}{5}\) = [ 3\(\frac{1}{15}\)]

Q8) \(\frac{1}{2}\) + \(\frac{2}{9}\) = [ \(\frac{13}{18}\)]

Q8) \(\frac{1}{2}\) - \(\frac{5}{12}\) = [ \(\frac{1}{12}\)]

Q8) 2\(\frac{2}{5}\) - 1\(\frac{7}{8}\) = [ \(\frac{21}{40}\)]

Q9) \(\frac{5}{9}\) + \(\frac{1}{4}\) = [ \(\frac{29}{36}\)]

Q9) \(\frac{4}{7}\) - \(\frac{1}{3}\) = [ \(\frac{5}{21}\)]

Q9) 1\(\frac{5}{6}\) - 1\(\frac{2}{3}\) = [ \(\frac{1}{6}\)]

Q10) \(\frac{1}{2}\) + \(\frac{1}{3}\) = [ \(\frac{5}{6}\)]

Q10) \(\frac{3}{4}\) - \(\frac{1}{3}\) = [ \(\frac{5}{12}\)]

Q10) 1\(\frac{1}{3}\) + \(\frac{1}{2}\) = [ 1\(\frac{5}{6}\)]