Mr Daniels Maths
Fraction Subtraction

Set 1

Set 2

Set 3

Q1) \(\frac{2}{3}\) - \(\frac{1}{3}\) = [ \(\frac{1}{3}\)]

Q1) 1\(\frac{1}{4}\) - \(\frac{5}{7}\) = [ \(\frac{15}{28}\)]

Q1) 5\(\frac{1}{2}\) - 1\(\frac{7}{19}\) = [ 4\(\frac{5}{38}\)]

Q2) \(\frac{5}{7}\) - \(\frac{1}{2}\) = [ \(\frac{3}{14}\)]

Q2) 1\(\frac{1}{2}\) - \(\frac{8}{9}\) = [ \(\frac{11}{18}\)]

Q2) 3\(\frac{1}{2}\) - 1\(\frac{8}{13}\) = [ 1\(\frac{23}{26}\)]

Q3) \(\frac{3}{5}\) - \(\frac{1}{3}\) = [ \(\frac{4}{15}\)]

Q3) 1\(\frac{2}{5}\) - \(\frac{5}{8}\) = [ \(\frac{31}{40}\)]

Q3) 1\(\frac{7}{11}\) - 1\(\frac{3}{5}\) = [ \(\frac{2}{55}\)]

Q4) \(\frac{4}{7}\) - \(\frac{2}{7}\) = [ \(\frac{2}{7}\)]

Q4) 1\(\frac{1}{3}\) - \(\frac{1}{2}\) = [ \(\frac{5}{6}\)]

Q4) 2\(\frac{1}{4}\) - 1\(\frac{5}{7}\) = [ \(\frac{15}{28}\)]

Q5) \(\frac{4}{5}\) - \(\frac{3}{4}\) = [ \(\frac{1}{20}\)]

Q5) 1\(\frac{2}{7}\) - \(\frac{3}{4}\) = [ \(\frac{15}{28}\)]

Q5) 2\(\frac{3}{5}\) - 1\(\frac{1}{3}\) = [ 1\(\frac{4}{15}\)]

Q6) \(\frac{3}{5}\) - \(\frac{1}{2}\) = [ \(\frac{1}{10}\)]

Q6) 1\(\frac{3}{4}\) - \(\frac{4}{5}\) = [ \(\frac{19}{20}\)]

Q6) 2\(\frac{4}{5}\) - 1\(\frac{2}{5}\) = [ 1\(\frac{2}{5}\)]

Q7) \(\frac{2}{3}\) - \(\frac{2}{9}\) = [ \(\frac{4}{9}\)]

Q7) 1\(\frac{1}{2}\) - \(\frac{3}{4}\) = [ \(\frac{3}{4}\)]

Q7) 3\(\frac{2}{3}\) - 1\(\frac{3}{7}\) = [ 2\(\frac{5}{21}\)]

Q8) \(\frac{4}{5}\) - \(\frac{2}{7}\) = [ \(\frac{18}{35}\)]

Q8) 1\(\frac{1}{4}\) - \(\frac{4}{7}\) = [ \(\frac{19}{28}\)]

Q8) 3\(\frac{1}{4}\) - 1\(\frac{2}{3}\) = [ 1\(\frac{7}{12}\)]

Q9) \(\frac{2}{3}\) - \(\frac{3}{7}\) = [ \(\frac{5}{21}\)]

Q9) 1\(\frac{1}{2}\) - \(\frac{4}{5}\) = [ \(\frac{7}{10}\)]

Q9) 2\(\frac{1}{3}\) - 1\(\frac{2}{5}\) = [ \(\frac{14}{15}\)]

Q10) \(\frac{2}{3}\) - \(\frac{3}{8}\) = [ \(\frac{7}{24}\)]

Q10) 1\(\frac{1}{6}\) - \(\frac{3}{4}\) = [ \(\frac{5}{12}\)]

Q10) 2\(\frac{3}{5}\) - 1\(\frac{2}{7}\) = [ 1\(\frac{11}{35}\)]