Q1) $1 \over{ \sqrt{ 8}}$ = [ $2\sqrt{2}\over{ 8}$]

Q1) $3 \over{ \sqrt{ 7}}$ = [ $3\sqrt{7}\over{7}$]

Q1) ${1} \over{ 3 + \sqrt 5}$ = [ ${ 3 - \sqrt 5} \over4$]

Q2) $1 \over{ \sqrt{ 3}}$ = [ $\sqrt{3}\over{ 3}$]

Q2) $2 \over{ \sqrt{ 6}}$ = [ $\sqrt{6}\over{3}$]

Q2) ${1} \over{ 3 - \sqrt 2}$ = [ ${ 3 + \sqrt 2} \over7$]

Q3) $1 \over{ \sqrt{ 3}}$ = [ $\sqrt{3}\over{ 3}$]

Q3) $4 \over{ \sqrt{ 8}}$ = [ $\sqrt{2}$]

Q3) ${1} \over{ 5 + \sqrt 3}$ = [ ${ 5 - \sqrt 3} \over22$]

Q4) $1 \over{ \sqrt{ 8}}$ = [ $2\sqrt{2}\over{ 8}$]

Q4) $4 \over{ \sqrt{ 5}}$ = [ $4\sqrt{5}\over{5}$]

Q4) ${1} \over{ 3 - \sqrt 2}$ = [ ${ 3 + \sqrt 2} \over7$]

Q5) $1 \over{ \sqrt{ 7}}$ = [ $\sqrt{7}\over{ 7}$]

Q5) $2 \over{ \sqrt{ 2}}$ = [ $\sqrt{2}$]

Q5) ${1} \over{ 4 - \sqrt 3}$ = [ ${ 4 + \sqrt 3} \over13$]