Q1) $1 \over{ \sqrt{ 6}}$ = [ $\sqrt{6}\over{ 6}$]

Q1) $5 \over{ \sqrt{ 5}}$ = [ $\sqrt{5}$]

Q1) ${1} \over{ 3 + \sqrt 3}$ = [ ${ 3 - \sqrt 3} \over6$]

Q2) $1 \over{ \sqrt{ 6}}$ = [ $\sqrt{6}\over{ 6}$]

Q2) $4 \over{ \sqrt{ 10}}$ = [ $2\sqrt{10}\over{5}$]

Q2) ${1} \over{ 5 - \sqrt 5}$ = [ ${ 5 + \sqrt 5} \over20$]

Q3) $1 \over{ \sqrt{ 7}}$ = [ $\sqrt{7}\over{ 7}$]

Q3) $2 \over{ \sqrt{ 2}}$ = [ $\sqrt{2}$]

Q3) ${1} \over{ 5 - \sqrt 5}$ = [ ${ 5 + \sqrt 5} \over20$]

Q4) $1 \over{ \sqrt{ 7}}$ = [ $\sqrt{7}\over{ 7}$]

Q4) $3 \over{ \sqrt{ 7}}$ = [ $3\sqrt{7}\over{7}$]

Q4) ${1} \over{ 4 + \sqrt 3}$ = [ ${ 4 - \sqrt 3} \over13$]

Q5) $1 \over{ \sqrt{ 10}}$ = [ $\sqrt{10}\over{ 10}$]

Q5) $4 \over{ \sqrt{ 2}}$ = [ $2\sqrt{2}$]

Q5) ${1} \over{ 5 - \sqrt 5}$ = [ ${ 5 + \sqrt 5} \over20$]