Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \(15z + 5 = 65\) [ \( z = 4\)]

Q1) \(7(z -3) = 42\) [ z= \(9\)]

Q1) 10(5z -4) = 60 [ z = 2]

Q2) \( {x\over7}-6 = 3\) [ \(x= 63\)]

Q2) \(9(z + 8) = 135\) [ z= \(7\)]

Q2) 4(2z -4) = 8 [ z = 3]

Q3) \(19y -7 = 126\) [ \( y = 7\)]

Q3) \(4(x + 9) = 48\) [ x= \(3\)]

Q3) 4(3z -2) = 40 [ z = 4]

Q4) \(14w -8 = 34\) [ \( w = 3\)]

Q4) \(7(y + 10) = 140\) [ y= \(10\)]

Q4) 4(4z -5) = 60 [ z = 5]

Q5) \( {x\over10}-8 = 2\) [ \(x= 100\)]

Q5) \(4(y + 8) = 52\) [ y= \(5\)]

Q5) 3(4x -7) = 3 [ x = 2]

Q6) \(3w + 3 = 12\) [ \( w = 3\)]

Q6) \(8(w + 7) = 136\) [ w= \(10\)]

Q6) 2(7z -10) = 92 [ z = 8]

Q7) \( {z\over10}+6 = 15\) [ \(z= 90\)]

Q7) \(10(z + 9) = 110\) [ z= \(2\)]

Q7) 3(2w + 2) = 18 [ w = 2]

Q8) \(10y -10 = 50\) [ \( y = 6\)]

Q8) \(6(x + 6) = 96\) [ x= \(10\)]

Q8) 4(4w -2) = 88 [ w = 6]

Q9) \( {x\over3}+9 = 17\) [ \(x= 24\)]

Q9) \(6(y + 2) = 54\) [ y= \(7\)]

Q9) 4(2z + 3) = 92 [ z = 10]

Q10) \( {y\over10}+6 = 13\) [ \(y= 70\)]

Q10) \(5(y + 4) = 45\) [ y= \(5\)]

Q10) 3(8x + 7) = 93 [ x = 3]