Mr Daniels Maths
Solving Equations 3 Brackets

Set 1

Set 2

Set 3

Q1) \(9w + 7 = 43\) [ \( w = 4\)]

Q1) \(8(w + 5) = 120\) [ w= \(10\)]

Q1) 3(6z -8) = 84 [ z = 6]

Q2) \(6y + 2 = 50\) [ \( y = 8\)]

Q2) \(8(z + 6) = 120\) [ z= \(9\)]

Q2) 5(7w -9) = 95 [ w = 4]

Q3) \(8z + 5 = 29\) [ \( z = 3\)]

Q3) \(9(y + 3) = 108\) [ y= \(9\)]

Q3) 7(3y + 4) = 70 [ y = 2]

Q4) \(19z + 10 = 200\) [ \( z = 10\)]

Q4) \(10(w + 9) = 180\) [ w= \(9\)]

Q4) 9(3x -4) = 45 [ x = 3]

Q5) \( {w\over7}+7 = 14\) [ \(w= 49\)]

Q5) \(6(y + 3) = 36\) [ y= \(3\)]

Q5) 2(5y + 10) = 60 [ y = 4]

Q6) \(7y + 6 = 76\) [ \( y = 10\)]

Q6) \(6(y -6) = 6\) [ y= \(7\)]

Q6) 3(3x -3) = 72 [ x = 9]

Q7) \( {y\over4}-8 = 2\) [ \(y= 40\)]

Q7) \(9(z -8) = 18\) [ z= \(10\)]

Q7) 4(3y -6) = 24 [ y = 4]

Q8) \(16w -6 = 122\) [ \( w = 8\)]

Q8) \(2(y -5) = 10\) [ y= \(10\)]

Q8) 8(3x -10) = -8 [ x = 3]

Q9) \( {z\over9}+7 = 14\) [ \(z= 63\)]

Q9) \(3(x -3) = 9\) [ x= \(6\)]

Q9) 2(8w -7) = 50 [ w = 4]

Q10) \(14z -7 = 49\) [ \( z = 4\)]

Q10) \(7(y -6) = 21\) [ y= \(9\)]

Q10) 6(4x -10) = 36 [ x = 4]