Mr Daniels Maths
Surds:Division

Set 1

Set 2

Set 3

Q1) \(\sqrt 20 \over{ \sqrt{ 10}} \) = [ \(\sqrt{2}\)]

Q1) \(4 \sqrt 18 \over{ \sqrt 6} \) = [ \(4\sqrt{3}\)]

Q1) \(8 \sqrt 20 \over{ 4 \sqrt 4} \) = [ \(2\sqrt{5}\)]

Q2) \(\sqrt 16 \over{ \sqrt{ 2}} \) = [ \(2\sqrt{2}\)]

Q2) \(2 \sqrt 80 \over{ \sqrt 10} \) = [ \(4\sqrt{2}\)]

Q2) \(8 \sqrt 12 \over{ 2 \sqrt 3} \) = [ \(8\)]

Q3) \(\sqrt 16 \over{ \sqrt{ 8}} \) = [ \(\sqrt{2}\)]

Q3) \(4 \sqrt 10 \over{ \sqrt 5} \) = [ \(4\sqrt{2}\)]

Q3) \(25 \sqrt 15 \over{ 5 \sqrt 5} \) = [ \(5\sqrt{3}\)]

Q4) \(\sqrt 9 \over{ \sqrt{ 1}} \) = [ \(3\)]

Q4) \(5 \sqrt 10 \over{ \sqrt 5} \) = [ \(5\sqrt{2}\)]

Q4) \(6 \sqrt 10 \over{ 3 \sqrt 5} \) = [ \(2\sqrt{2}\)]

Q5) \(\sqrt 27 \over{ \sqrt{ 9}} \) = [ \(\sqrt{3}\)]

Q5) \(5 \sqrt 54 \over{ \sqrt 9} \) = [ \(5\sqrt{6}\)]

Q5) \(20 \sqrt 9 \over{ 5 \sqrt 3} \) = [ \(4\sqrt{3}\)]

Q6) \(\sqrt 100 \over{ \sqrt{ 10}} \) = [ \(\sqrt{10}\)]

Q6) \(2 \sqrt 36 \over{ \sqrt 4} \) = [ \(6\)]

Q6) \(12 \sqrt 20 \over{ 4 \sqrt 4} \) = [ \(3\sqrt{5}\)]

Q7) \(\sqrt 32 \over{ \sqrt{ 4}} \) = [ \(2\sqrt{2}\)]

Q7) \(2 \sqrt 64 \over{ \sqrt 8} \) = [ \(4\sqrt{2}\)]

Q7) \(8 \sqrt 12 \over{ 4 \sqrt 4} \) = [ \(2\sqrt{3}\)]

Q8) \(\sqrt 60 \over{ \sqrt{ 10}} \) = [ \(\sqrt{6}\)]

Q8) \(2 \sqrt 21 \over{ \sqrt 3} \) = [ \(2\sqrt{7}\)]

Q8) \(4 \sqrt 10 \over{ 2 \sqrt 2} \) = [ \(2\sqrt{5}\)]

Q9) \(\sqrt 8 \over{ \sqrt{ 4}} \) = [ \(\sqrt{2}\)]

Q9) \(2 \sqrt 54 \over{ \sqrt 6} \) = [ \(6\)]

Q9) \(10 \sqrt 15 \over{ 5 \sqrt 5} \) = [ \(2\sqrt{3}\)]

Q10) \(\sqrt 24 \over{ \sqrt{ 8}} \) = [ \(\sqrt{3}\)]

Q10) \(2 \sqrt 6 \over{ \sqrt 1} \) = [ \(2\sqrt{6}\)]

Q10) \(12 \sqrt 15 \over{ 4 \sqrt 5} \) = [ \(3\sqrt{3}\)]